C2 Logarithms help needed!

Hi I have a question I just can't get my head around, hopefully someone could help me out!

1. Express as a single logarithm-

log(x+1)-log(x-6)+2logx

Reply 1

Notnek

Original post by ViciousPenguin

Hi I have a question I just can't get my head around, hopefully someone could help me out!

1. Express as a single logarithm-

log(x+1)-log(x-6)+2logx

What have you tried? Do you know how to combine sums of logs?

This will help:

2\log x = \log x^2

Reply 2

shawn_o1

log(ab) = log(a) + log(b)
log(a/b) = log(a) - log(b)
log(a^k) = k log(a)

Isn't that in the C2 text book if you have one?

Reply 3

Chlorophile

Original post by ViciousPenguin

Hi I have a question I just can't get my head around, hopefully someone could help me out!

1. Express as a single logarithm-

log(x+1)-log(x-6)+2logx

Remember that log(a)+log(b)=log(a*b) and log(a)-log(b)=log(a/b)
Also remember that xlog(a)=log(a^x)

That's all you need for this question.

Reply 4

TenOfThem

Original post by ViciousPenguin

Hi I have a question I just can't get my head around, hopefully someone could help me out!

1. Express as a single logarithm-

log(x+1)-log(x-6)+2logx

\log (a) + \log (b) = \log (ab)

\log (a) - \log (b) = \log (\frac{a}{b})

m\log (a) = \log (a^m)

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C2 Logarithms help needed!

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