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S1 question help?

Not really good at s1, any revision tips?
Need help on this question:
1) An adult evening class has 14 students. The ages of these students have a mean of 31.2 years and standard deviation of 7.4 years.
A new student who is exactly 42 years old joins the class. Calculate the mean and standard deviation of the 15 students now in the group.

Could you explain to me?
Thank you :smile:
mean = sum of x/n

so sum of x = n x mean
14x 31.2 =436.8

adding the new student means that sum of x is now 436.8 + 42 = 478.8

therefore, new mean = sum of x/n
478.8/15 = 31.92



for the standard deviation, for the original class:

(standard deviation is the square root of variance)
σ2 = Σx2/n mean2

7.42 = Σx2/14 31.22

rearrange that to get Σx2 = 14394.8

then, adding in the new student:

14394.8 + 422 = 16158.8 (this is the new Σx2)

therefore, the new standard deviation is the square root of:

16158.8/15 31.922
Reply 2
Original post by Wiggledinho
mean = sum of x/n

so sum of x = n x mean
14x 31.2 =436.8

adding the new student means that sum of x is now 436.8 + 42 = 478.8

therefore, new mean = sum of x/n
478.8/15 = 31.92



for the standard deviation, for the original class:

(standard deviation is the square root of variance)
σ2 = Σx2/n mean2

7.42 = Σx2/14 31.22

rearrange that to get Σx2 = 14394.8

then, adding in the new student:

14394.8 + 422 = 16158.8 (this is the new Σx2)

therefore, the new standard deviation is the square root of:

16158.8/15 31.922


thank you! :smile:

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