Year 12s: what will be the first way you research your future options? >>

Year 12s: what will be the first way you research your future options? >>

Year 12s: what will be the first way you research your future options? >>

c2-logs

Can someone help me with the following question.I have done part A but cant seem to do part b.
So far I have worked out that y=2x from the 3^y=9^x
For the first part I did
log2y^2=log2root3+log2x
Then
log2y^2=log2xroot3
so y^2=xroot3?
Am I doing this right?
Thanks :smile:

:smile:

(edited 10 years ago)

20140413_142705-1.jpg112.4KB

Yes, but you meant

y^2

in your last line. Don't forget to discard the zero solution, for the logarithm is undefined at zero.

OP

Original post by Ateo

Yes, but you meant

y^2

in your last line. Don't forget to discard the zero solution, for the logarithm is undefined at zero.

How do I solve for x from here? Being really daft and can't seem to figure it out.
If I square both sides. I get

y^4=3x^2

?

Original post by Super199

How do I solve for x from here? Being really daft and can't seem to figure it out.
If I square both sides. I get

y^4=3x^2

?

y^2 = (2x)^2 = 4x^2 = \sqrt{3} x

OP

Original post by Ateo

y^2 = (2x)^2 = 4x^2 = \sqrt{3} x

Ah cheers got it now thanks :smile:

:smile:

How do I do

3^{2x}+3^{x+1}-10=0

?

Original post by Super199

Ah cheers got it now thanks :smile:

:smile:

How do I do

3^{2x}+3^{x+1}-10=0

?

Set

y=3^x

Kvothe the Arcane

Original post by Super199

Ah cheers got it now thanks :smile:

:smile:

How do I do

3^{2x}+3^{x+1}-10=0

?

3^{2x}+3^{x+1}-10=0=(3^x)^2+3 \times 3^x -10

OP

Original post by keromedic

3^{2x}+3^{x+1}-10=0=(3^x)^2+3 \times 3^x -10

Solved it now but thanks though :smile:

:smile:

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