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Calculus

How do you find the rate of change of the perimeter of a right triangle knowing that the perimeter is P=15(1+sinx+cosx)


thank you
Original post by sabi06
How do you find the rate of change of the perimeter of a right triangle knowing that the perimeter is P=15(1+sinx+cosx)


thank you


The rate of change is dP/dx

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