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Zenarthra

Is there something wrong in my workings?

Thanks!

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Reply 1

TeeEm

Original post by Zenarthra

Is there something wrong in my workings?

Thanks!

I cannot see the workings very clearly
have you done part (a)?
part (b)?

etc

Reply 2

Notnek

Original post by Zenarthra

Is there something wrong in my workings?

Thanks!

Third line from bottom, you have used:

\displaystyle \frac{d^2 t}{dx^2} = \frac{1}{\left(\frac{d^2 x}{dt^2}\right)}

But that is not true in general.

Reply 3

Zenarthra

Original post by notnek

Third line from bottom, you have used:

\displaystyle \frac{d^2 t}{dx^2} = \frac{1}{\left(\frac{d^2 x}{dt^2}\right)}

But that is not true in general.

ahh i got it now thanks

(edited 9 years ago)

Reply 4

Ilovemaths96

Original post by Zenarthra

Is there something wrong in my workings?

Thanks!

wher did you get the question from?

Reply 5

TeeEm

Original post by Ilovemaths96

wher did you get the question from?

this an AQA FP3 question

Reply 6

Ilovemaths96

Original post by TeeEm

this an AQA FP3 question

cool thanks

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