Maths vs Dentistry?

My friend just did a Maths degree and got a 1st using Wolfram and his graphical calculator (to be fair he got a top of the range one, Casio i believe).

No you can apply to finance from a dentistry degree and those who get finance jobs are accounting and law/Econ graduates not maths grads.

Also dentists are guaranteed near £100k.


Posted from TSR Mobile

Stop. Stop. Just stop. You are stupid, incredibly stupid. Don't talk about things you know nothing about.

If I were to comment on matters of nuclear physics and say that nuclear fusion could never happen because I don't understand it then I would be stupid. Like you commenting on maths and IB and "jobs in the city".

A maths degree can not be done on a calculator.

I will give you a first year first term maths question and please tell me the solution using a calculator...

"A sequence $a_n$ is called cauchy if for all $\epsilon > 0$ there exists a N > 0 such that for m,n > N $|a_n - a_m| < \epsilon$

Suppose $(a_n) \rightarrow a$. Show that $|a_n - a_m| \leq |a_n - a| + |a - a_m|$. Use this fact to prove that $(a_n)$ is Cauchy."

Now this question is so easy for a first year student it's almost trivial. So please PLEASE do it on a calculator. Or explain how it could be done on a calculator.

All three degrees you stated are very well respected. Just please don't say thing you know nothing about.

Also, I know many people on my course (maths) who have jobs within investment banks. I myself have a job as an actuary (finance job in the city).

Genuinely can't tell if this thread is a joke or not any more...

My friend just did a Maths degree and got a 1st using Wolfram and his graphical calculator (to be fair he got a top of the range one, Casio i believe).

Please tell me where he studied his degree. I don't believe you. It literally isn't possible. He would have needed to understand at least a basic level of proof.

I work in finance and I'm a maths grad. Ive had two graduate jobs both in finance. Anyone with any degree can apply to finance grad schemes..


Posted from TSR Mobile

From where? If it was london met then I can believe that.

Please tell me where he studied his degree. I don't believe you. It literally isn't possible. He would have needed to understand at least a basic level of proof.

un+p−un=∑k=1pun+k−un+k−1|un+p−un|≤∑k=0p−1|un+k+1−un+k|≤∑k=0p−1bn+k≤bn1−b
so
when n→∞ , that is u is a Cauchy sequence.

Sorry my calculator put u rather than n

0/7.

I taught the module this year for that question and had access to the mark scheme. You just got 0/7. What you put there was literally nonsense. You just proved me correct for anyone who understands anyone who knows anything about maths.

Probably did a numerate degree with some maths component. Every maths degree would have an element of proof


Posted from TSR Mobile

Wawrick

According to the above - no he didn't.



Now I know you're joking...

He didn't. He really didn't do a maths degree at Warwick on a calculator and get a first. I know it's impossible - for a start all maths exams at Warwick are non-calculator - please explain how you would do it on a calculator

He snuck his in to the exams!

This thread is ridiculous. He didn't because you can't do a Warwick paper on a calculator. I know this because I'm at Warwick.

I'm getting out of this thread. Dentistry is well respected which is what you want to hear.

In general you are arrogant and know nothing of what you talk. I doubt you will get into dentistry, or if you already have that shows you it is not as respected as you think - as they let you in.

Good luck.

...

"A sequence $a_n$ is called cauchy if for all $\epsilon > 0$ there exists a N > 0 such that for m,n > N $|a_n - a_m| < \epsilon$

Suppose $(a_n) \rightarrow a$. Show that $|a_n - a_m| \leq |a_n - a| + |a - a_m|$. Use this fact to prove that $(a_n)$ is Cauchy."
...

Thought I'd take a stab let me know if this is right I'm new to proof based maths.

Since $\displaystyle a_n \rightarrow 0$ we know $\displaystyle \forall ~\epsilon>0~\exists ~N\in\mathbb{N}~s.t~|a_n-a|<\frac{\epsilon}{2}~\forall~n>N$ so $\displaystyle \forall~m>n>0$ we have $\displaystyle |a_m-a|<\frac{\epsilon}{2}$
we know by the triangle inequality that $\displaystyle |a_n-a_m|=|(a_n-a)-(a_m-a)|\leq |a_n-a|+|a_m-a|\leq\frac{\epsilon}{2}+ \frac{\epsilon}{2}=\epsilon$.

Since $\displaystyle \epsilon$ was arbitrary we conclude $\displaystyle a_n$ is Cauchy.

Whoever thinks you can do this on a calculator is either trolling or I feel really sorry for them. Maths and Dentistry are both respected degrees so do whichever one you think you will enjoy more. I really enjoy a lot of the areas in maths so I decided to do that even though I'm not amazing at it.

What calculator you got? Mine is poverty Panasonic, may have to upgrade to yours.

Wawrick

I just used Wolfram Alpha, I'm going to sneak it in to all my exams so I can get an easy first.

Then I'm going to use it to prove Goldbach's conjecture and get $1,000,000 then I'm going to invest it and make more millions then I'm going to party, take drugs and sleep with 50 women a week because I can YOLO.

Total bull**** unless he snuck in a super computer with automatic proof software.