Integral[ 2/(2x-1)] is ln(2x-1) not 2ln(2x-1) similar thing with the other term
Original post by bl64
use the partial fractions to find the integral of 7/(2x-1)(3x+2) dx
I did 7= A(3x+2) + B(2x-1) getting A = 2 B= -3
so i integrated and got 2ln(2x-1) - 3ln(3x-2) the answer book gave ln(2x-1/3x+2) + c where did i go wrong?
I did 7= A(3x+2) + B(2x-1) getting A = 2 B= -3
so i integrated and got 2ln(2x-1) - 3ln(3x-2) the answer book gave ln(2x-1/3x+2) + c where did i go wrong?
int[2/(2x-1)] = ln|2x-1| + C and similarly the other
you have not divided by 2 from the 2x-1
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