Binomial distribution problem

username1533709

7ii
I haven't finished it but am I on the right path and if so how would I finish working it out.

Reply 1

username1533709

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Reply 2

Wahid-r

Original post by Kadak

7ii
I haven't finished it but am I on the right path and if so how would I finish working it out.

Start here, cancel (divide through) as appropriate and then solve for p. Don't compute it all since there are a lot of cancellations.

Can't seem to upload my picture.

But here: (21c10) p^10 (1-p)^11 = (21c9) p^9 (1-p)^12

(edited 9 years ago)

Got it now lol:

Original post by Wahid-r

Got it now lol:

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Here is what I've done so far and I'm stuck.

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Reply 5

samb1234

Original post by Kadak

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Here is what I've done so far and I'm stuck.

Do you know the answer?

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Reply 6

Wahid-r

Original post by Kadak

Posted from TSR Mobile

Here is what I've done so far and I'm stuck.

Can you spot all the cancellations now?

Divide by 21!, divide by (1-p)^11, for instance. Once you cancel everything it becomes a very simple equation.