*MEGATHREAD* - BMAT for 2016 Entry Discussion

thanks! i got that there were 720 possibilities but i don't understand how you got the combinations of how many will alternate! please could you explain that bit

Hopefully this makes sense haha...

Ok if you think about it there are six places:

1st place: You have three choices of red
2nd place: You have three choices of yellow
3rd place: You have two choices of red (one is already used in the 1st place)
4th place: You have two choices of yellow (one is already used in the 2nd place)
5th place: You have one choice of red (two used up)
6th place You have one choice of yellow (two used up)

This gives you 36 possibilities but since you started with red, you can also start with yellow. So its 36 times 2 = 72

please could you help with this one!

I answered it a different way, this makes sense for me just thought I'd share haha

please could you also explain why 10 is b?

thanks thats really helpful as well! this 2007 paper is actually really hard

Ok, give me a second to solve this.

thanks! can you also do 12 as well as i got that wrong too ahahah

Gosh, this is confusing haha

Would anyone be able to help me with this question? Thanks

Omg, I did this question ages ago but I forgot how to do it! Which paper is it from?
Actually i attempted this question got it wrong, spent ages figuring it out, asked my friends and it got me no where l o l

I don't know if relative means dividing to be honest...does my calculations make sense? I just followed the charts.

Gosh, this is confusing haha

any idea how to work this out quickly?

Is it D?