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C1 OCR solomon paper increasing functions

Hi can anyone help me with Question 3 on the OCR Solomon paper H

paper--https://a9497d7f220e174d38d014b2b1d86a68bedc42a8.googledrive.com/host/0B1ZiqBksUHNYNExoNEtSS1ViN2c/for-OCR/Solomon%20H%20QP%20-%20C1%20OCR.pdf

Mark scheme -- https://a9497d7f220e174d38d014b2b1d86a68bedc42a8.googledrive.com/host/0B1ZiqBksUHNYNExoNEtSS1ViN2c/for-OCR/Solomon%20H%20MS%20-%20C1%20OCR.pdf

I cant understand why dy/dx has been solved greater than or equal to 0 do you not show that a function is increasing my solving dy/dx> 0
Reply 1
Original post by admirableyellow
Hi can anyone help me with Question 3 on the OCR Solomon paper H

paper--https://a9497d7f220e174d38d014b2b1d86a68bedc42a8.googledrive.com/host/0B1ZiqBksUHNYNExoNEtSS1ViN2c/for-OCR/Solomon%20H%20QP%20-%20C1%20OCR.pdf

Mark scheme -- https://a9497d7f220e174d38d014b2b1d86a68bedc42a8.googledrive.com/host/0B1ZiqBksUHNYNExoNEtSS1ViN2c/for-OCR/Solomon%20H%20MS%20-%20C1%20OCR.pdf

I cant understand why dy/dx has been solved greater than or equal to 0 do you not show that a function is increasing my solving dy/dx> 0

It's a mistake. The function is stationary at x=3x=-3 and x=13x=\frac{1}{3}.
Reply 2
Original post by notnek
It's a mistake. The function is stationary at x=3x=-3 and x=13x=\frac{1}{3}.


AFAIK, increasing is 0\geq 0 and strictly increasing is >0>0.

Edit: after looking it up, I think I agree with you. f(b)f(a)f(b) \geq f(a) for b>ab>a is increasing - which is where my confusion stemmed from. Apologies.
(edited 7 years ago)
Original post by notnek
It's a mistake. The function is stationary at x=3x=-3 and x=13x=\frac{1}{3}.


Glad its a mistake. Cheers for clearing that up

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