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AQA A2 Physics 2016 Paper 4

Hi,

I'm unable to understand this question. Can someone explain this please.

23. A train is travelling at 20 m s–1 along a horizontal track through a uniform magnetic field of flux density 4.0 × 10–5 T acting vertically downwards. What is the emf induced between the ends of an axle 1.5 m long?

A 3.0 × 10−6 V
B 5.3 × 10−4 V
C 1.2 × 10−3 V
D 7.5 × 105 V

Examiner Report - 68% of the students did this correctly. One in
five of them selected distractor B, which could follow from an incorrect formula or substitution = B v/ l).

With no current given how is it possible to derive the solution.
Original post by Infinity43965
Hi,

I'm unable to understand this question. Can someone explain this please.

23. A train is travelling at 20 m s–1 along a horizontal track through a uniform magnetic field of flux density 4.0 × 10–5 T acting vertically downwards. What is the emf induced between the ends of an axle 1.5 m long?

A 3.0 × 10−6 V
B 5.3 × 10−4 V
C 1.2 × 10−3 V
D 7.5 × 105 V

Examiner Report - 68% of the students did this correctly. One in
five of them selected distractor B, which could follow from an incorrect formula or substitution = B v/ l).

With no current given how is it possible to derive the solution.


hey :smile:

so image the axle as one rod passing through a magnetic field, the change in flux is constant correct? as its constantly travelling throught the field. hence an emf is induced equaly to the Blv = emf. which can be derived from BIL= F and w=fs

hence blv=E , plug all those values in and bingo! thats your answer
Reply 2
Instead of F=BIL use F=BQv
W=Fs and F=BQv
F=W/s=BQv
W/Q=Bvs=emf
emf=4x10^-5 x 20 x1.5 =1.2x10^-3
--Basil osman
(edited 1 year ago)

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