for the mechansim of forming a tertiary amine, why is a primary amine used? i thought that once a secondary amine is made, it reacts with the haloalkane and then the tertairy amine reacts and so on replacing the H on the previous amine
for the mechansim of forming a tertiary amine, why is a primary amine used? i thought that once a secondary amine is made, it reacts with the haloalkane and then the tertairy amine reacts and so on replacing the H on the previous amine
for the mechansim of forming a tertiary amine, why is a primary amine used? i thought that once a secondary amine is made, it reacts with the haloalkane and then the tertairy amine reacts and so on replacing the H on the previous amine
reacting a primary amine with excess haloalkane with produce the secondary amine through nucleophilic substitution. Then the secondary amine will react with more excess haloalkane to produce tertiary amine and then quartenary ammoinum salt.
Even if you used ammonia, you can get a mixture of primary amine secondary amine, tertiary amine, quarternary ammonium salt via nucleophillc substituion reactions.
Thisshould help to show the pattern of the reaction. So even if you used primary amine, the reaction will produce tertiary amine. If you used secondary amine, you will produce tertiary amine. If you used ammonia, you will produce tertiary amine.
reacting a primary amine with excess haloalkane with produce the secondary amine through nucleophilic substitution. Then the secondary amine will react with more excess haloalkane to produce tertiary amine.
Even if you used ammonia, you can get a mixture of primary amine secondary amine, tertiary amine, quarternary ammonium salt via nucleophillc substituion reactions.
i don't understand the mechanism for the formation of the tertiary amine from the reaction of methylamine and chloroethane.
i don't understand the mechanism for the formation of the tertiary amine from the reaction of methylamine and chloroethane.
Mechanism
I was meant to mention "amine formed has +1 formal charge in the N atom" but mentioned "ammonium chloride" by mistake in the picture
I also have named the products wrongly in the picture by mistake. the ionic salt product formed at each stage should be called methyl ammonium chloride
The products depend on the ratio of the reactants. If excess haloalkane is used you will get a quaternary salt.
Thats correct, but you also have to note that the R-NH2 is acting as a base and a nucleophile. So for your single reaction (not the overall reaction), both the RNH2 molecules will be reacting with the R'Cl to produce R-NH3+Cl- and the secondary amine.