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Help I. Don’t get this q my exam final is in a week… the red is correct ans but idk how to do it I know that d2o removed OH but how do I know the rest

I don’t get the chemical shift I part why is it 2-3 isn’t that a c double bond o.
I mean for the first one the it’s A H attached to a So isn’t it 1-2??IMG_2611.jpeg
(edited 11 months ago)
Reply 1
what exam board is this from?
Reply 2
Original post by GhostHawk
what exam board is this from?

It’s ocr a
Plz help me
(edited 11 months ago)
Reply 3
Original post by Alevelhelp.1
Help I. Don’t get this q my exam final is in a week… the red is correct ans but idk how to do it I know that d2o removed OH but how do I know the rest

I don’t get the chemical shift I part why is it 2-3 isn’t that a c double bond o.
I mean for the first one the it’s A H attached to a So isn’t it 1-2??IMG_2611.jpeg


When you shake it with D2O, some of the hydrogens get replaced by deuteriums.
The hydrogens this happens to are hydroxyl (-OH) and amine group ones the hydroxyl one can be deprotonated (so you get –O-) and the amine one can be protonated/deuterated (so you get –NH3+, –NH2D+, NHD2+, ND3+ remember in solution there is interchange)… so these groups will not appear in the 1H NMR spectrum.

The remaining hydrogens are the ones attached to the carbons.
For the CH hydrogen, there is only one hydrogen atom in this environment, so the relative peak area = 1. There are two hydrogens attached to the adjacent carbon, so the splitting pattern is a triplet (as n + 1 = 2 + 1 = 3).
For the CH2 hydrogens, the same applies. There are two of these hydrogens, so relative peak area = 2. There is one "adjacent" hydrogen, so the splitting pattern is a doublet (1 + 1 = 2).


https://en.wikipedia.org/wiki/Hydrogen–deuterium_exchange
https://www.chemguide.co.uk/analysis/nmr/highres.html (see "A clever way of picking out the -OH peak")
https://chemguide.co.uk/organicprops/aminoacids/acidbase.html

And
https://cpb-us-e1.wpmucdn.com/sites.ucsc.edu/dist/9/291/files/2015/11/IR-Table-1.pdf
At the top of page 3 there is a nice little diagram of approximate chemical shifts :smile:
Reply 4
Original post by bl0bf1sh
When you shake it with D2O, some of the hydrogens get replaced by deuteriums.
The hydrogens this happens to are hydroxyl (-OH) and amine group ones the hydroxyl one can be deprotonated (so you get –O-) and the amine one can be protonated/deuterated (so you get –NH3+, –NH2D+, NHD2+, ND3+ remember in solution there is interchange)… so these groups will not appear in the 1H NMR spectrum.

The remaining hydrogens are the ones attached to the carbons.
For the CH hydrogen, there is only one hydrogen atom in this environment, so the relative peak area = 1. There are two hydrogens attached to the adjacent carbon, so the splitting pattern is a triplet (as n + 1 = 2 + 1 = 3).
For the CH2 hydrogens, the same applies. There are two of these hydrogens, so relative peak area = 2. There is one "adjacent" hydrogen, so the splitting pattern is a doublet (1 + 1 = 2).


https://en.wikipedia.org/wiki/Hydrogen–deuterium_exchange
https://www.chemguide.co.uk/analysis/nmr/highres.html (see "A clever way of picking out the -OH peak")
https://chemguide.co.uk/organicprops/aminoacids/acidbase.html

And
https://cpb-us-e1.wpmucdn.com/sites.ucsc.edu/dist/9/291/files/2015/11/IR-Table-1.pdf
At the top of page 3 there is a nice little diagram of approximate chemical shifts :smile:


Thank uuu
but I still don’t get the chemical shift part… in the exam I’m not gonna be given any thing apart from the pt and the nmr data and I’m still stuck on how to get 2-3 and 3.3-4.4 for the chemiscal shift paft
Reply 5
Original post by Alevelhelp.1
Thank uuu
but I still don’t get the chemical shift part… in the exam I’m not gonna be given any thing apart from the pt and the nmr data and I’m still stuck on how to get 2-3 and 3.3-4.4 for the chemiscal shift paft


I guess you would just read off the NMR chemical shifts diagram on the data sheet?
https://www.ocr.org.uk/Images/363792-unit-h032-and-h432-data-sheet.pdf
As the HC-C=O (corresponding to the triplet) is 2-3 ppm, and the HC-O (corresponding to the doublet) is around 3.3-4.4 ppm

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