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AQA(A) Physics Synoptic Paper PA10 - 17th June 2008

t-a-r-online

How did we find PA10?

Didn't think it was overly complicated; started off fairly nicely...

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Reply 1

Adamshields

I had a complete shocker. Think the nerves just got to me. Couldnt believe it. Goodbye, first choice uni!

Reply 2

t-a-r-online

Adamshields

I had a complete shocker. Think the nerves just got to me. Couldnt believe it. Goodbye, first choice uni!

I was like that for PA04, and was "goodbye Uni". Don't worry, I think the grade boundaries tend to be a little lower for Synoptic.

Reply 3

Adamshields

Last year 51/80 was an A in the synoptic paper. I reckon I'll be lucky to get in the 40s

Reply 4

HarisF1

It was an amazing paper.

Had everything I revised and what I didn't revise, I worked out on the dot.

Oh, and BTW, I completed it in 1hr 30mins. Surprised myself, there.

Reply 5

steelmole

Is this the one with the pre-release material? I'm not sure which exam code etc I did.

Reply 6

t-a-r-online

steelmole

Is this the one with the pre-release material? I'm not sure which exam code etc I did.

No.

It was AQA Spec A, Paper 10, PA10.

Reply 7

paul10590

Oh god, i couldn't rearrange the graph formula, find g, work out the jupiter comet velocity or rearrange the gravity = 0 for the jupiter + sun :'(

bye bye medicine!!

Reply 8

Wenzel

Most of it I found pretty good. Couldn't do the second part of the jupiter/sun question (where it told you Jupiters mass is 1040 times less than the Suns) and couldn't rearrange the graph equation. Overall I think I've got a B on that paper.

Reply 9

Zwitter Ion

I feel i've messed up terribly :frown:

easy marks aswelll!!

Reply 10

HarisF1

For the graph equation,

T=2pi sqrt (H-h)/g

T^2 = 4pi^2 (H-h)/g

So T^2 = a - bh = H*4pi^2/g - (h)*4pi^2/g

Reply 11

Adamshields

What were the boundaries for all the grades last year? I know than 51 was an A, but dont know what else you had to get for the other grades.

Reply 12

Adamshields

HarisF1

For the graph equation,

T=2pi sqrt (H-h)/g

T^2 = 4pi^2 (H-h)/g

So T^2 = a - bh = H*4pi^2/g - (h)*4pi^2/g

Phew!

i did crap :frown:

why do you care about grade boundaries> ? It doesn't affect the UMS, you need what you need not a grade ? :s-smilie:

Reply 15

HarisF1

For the mass one,

Do g= Gm/r for both bodies.

g = G*1040 / r

and

g =G*1/ r

Thats it.

r is the value calculated in the earlier part (minus) The zero g distance for the sun, and the zero g distance for jupiter

It gives an answer like 0.03* 10^-34

Which is zero.

Reply 16

Zwitter Ion

Adamshields

What were the boundaries for all the grades last year? I know than 51 was an A, but dont know what else you had to get for the other grades.