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Check My Integration
Hi
I've been asked to integrate between Pi/3 and 0: sec^3(x) . tan^3(x) dx
where u = sec(x) hence du/sec(x)tan(x) = dx
thus integrate sec^2(x)tan^2(x) du
to u^4 + 1 (since tan^2(x) + 1 = sec^2(x))
hence integrating this gives (u^5)/5 + u
sub sec(x) in for u and put in values giving (0.00625 + 0.5) - (1/5 + 1) = -0.69375
This seems a rather strange answer, spot any errors?
Streety
I've been asked to integrate between Pi/3 and 0: sec^3(x) . tan^3(x) dx
where u = sec(x) hence du/sec(x)tan(x) = dx
thus integrate sec^2(x)tan^2(x) du
to u^4 + 1 (since tan^2(x) + 1 = sec^2(x))
hence integrating this gives (u^5)/5 + u
sub sec(x) in for u and put in values giving (0.00625 + 0.5) - (1/5 + 1) = -0.69375
This seems a rather strange answer, spot any errors?
Streety
Cheers
Answer now comes out at 58/15 using u limits instead with out subbing u back into the original equation, do you get the same?
Answer now comes out at 58/15 using u limits instead with out subbing u back into the original equation, do you get the same?
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