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Chemistry exam question

Hey I need some help
Complete combustion of a hydrocarbon produced 0.66g of carbon dioxide and 0.225g of water.

Which of the following molecular formulae is consistent with these data?
A c3h6
B c3h8
C c6h6
D c6h10

The answer is D but how ?
I did the empirical formula and got ch4 .....
Okay...

X (being your hydrocarbon) --> nCO2 + mH2O
where m and n are integers

CO2 44gmol
H2O 18gmol

n = m/Mr

CO2 --> 0.66/44 = 0.015mol
H2O --> 0.225/18 = 0.0125mol

CO2 : H20
0.015 : 0.0125
1.2 : 1
6 : 5

X --> 6CO2 + 5H20
then you have 6 carbons and 10 hydrogens so get C6H10
Reply 2
Original post by hiddeninabook
Okay...

X (being your hydrocarbon) --> nCO2 + mH2O
where m and n are integers

CO2 44gmol
H2O 18gmol

n = m/Mr

CO2 --> 0.66/44 = 0.015mol
H2O --> 0.225/18 = 0.0125mol

CO2 : H20
0.015 : 0.0125
1.2 : 1
6 : 5

X --> 6CO2 + 5H20
then you have 6 carbons and 10 hydrogens so get C6H10

Thank you so much. I understand it completely.

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