Statistics

RLangdon569

8

Hi, any help on parts b and c would be greatly appreciated. No idea how to proceed with part c in particular

OP

Original post by RLangdon569

b) what if you define Y = 2X - 1 ?

Original post by RLangdon569

c) notice the probability of 1. This means your region for Y includes the entire sample space.

You know mu and sigma. So just work out least k so that the region

from mu-k*sigma
to mu+k*sigma

includes the entire sample space of Y.

(edited 2 years ago)

Reply 4

RLangdon569

OP

8

Original post by RDKGames

c) notice the probability of 1. This means your region for Y includes the entire sample space.

You know mu and sigma. So just work out least k so that the region

from mu-k*sigma
to mu+k*sigma

includes the entire sample space of Y.

Hi, thanks a lot for your help. I am not quite sure I understand your explanation for part c however

Reply 5

RLangdon569

OP

8

I get P(100-k(99/3)^0.5 < Y < 100+k(99/3)^0.5 ) . Is this correct ? If so, how do I progress ?

Reply 6

ghostwalker

17

Original post by RLangdon569

I get P(100-k(99/3)^0.5 < Y < 100+k(99/3)^0.5 ) . Is this correct ? If so, how do I progress ?

Close. Variance of Y is

\frac{1}{3}(n^2-1)

, not

\frac{1}{3}(n-1)

. And we want weak inequalities, not strict.

You need that interval to cover the whole sample space, viz. 1,3,5,....., 199.

So, the lower end must be less than or equal to 1, and the upper end greater than or equal to 199. So, what's the minimum value of k that will do that?

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