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AS level chemistry help- exam soon

A sample of a hydrocarbon with a mass of 7.2g contained 6.0g of carbon. What is the empirical formula of the hydrocarbon?


A CH2
B C5H12
C C6H6
D C7H6



The answer is B but I don't know how. could someone please explain?
Reply 1
so a hydrocarbon will only contain hydrogen and carbon.

therefore there is 6g of carbon and 1.2g of hydrogen.

You should be able to work it out from there?
mass of each -> mr > moles > /smallest mole
hii even im stuck in this. I got CH2.
Original post by lunariumxo
mass of each -> mr > moles > /smallest mole

i did this, but got A instead of B
Reply 5
hi! im actually doing this right now!

1) first work out mass
so hydrocarbon mass= 7.2g

carbon= 6g

hydrogen= hydrocarbon - carbon
= 7.2 - 6 = 1.2g

2) work out moles
carbon mol= 6/12= 0.5
hydrogen mol= 1.2/1 = 1.2

3) work out ratio
divide by the smallest to get ratio!:
carbon= 0.5/ 0.5= 1
hydrogen= 2.4

4) times till u get a whole number!
hydrogen= 2.4 x 5 = 12
therefore carbon= 1 x 5= 5


so therefore the empirical formula is C5H12

I hope this helped!!! :smile:
Original post by itss0ph
hi! im actually doing this right now!

1) first work out mass
so hydrocarbon mass= 7.2g

carbon= 6g

hydrogen= hydrocarbon - carbon
= 7.2 - 6 = 1.2g

2) work out moles
carbon mol= 6/12= 0.5
hydrogen mol= 1.2/1 = 1.2

3) work out ratio
divide by the smallest to get ratio!:
carbon= 0.5/ 0.5= 1
hydrogen= 2.4

4) times till u get a whole number!
hydrogen= 2.4 x 5 = 12
therefore carbon= 1 x 5= 5


so therefore the empirical formula is C5H12

I hope this helped!!! :smile:

Oh my gosh! Thank you so much. I didn't know that you'd have to multiply to get a whole number. I just rounded off the ratio 😂

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