Maths Difficulty.....Please Help Somebody :)

Bhaal85

The answer is:

Y=3((x-2)^2-2r1r3)

Expand this bracket and you get the original equation:

y = 3x^2 - 12x + 5

Reply 121

Unregistered

fantastico!!!! the minimum value, is the minimum value that the y coordinate can be, when we have found the value of x from solving that simple linear equation...i get it!!! and we find this minimum value (y co-ordinate), by solving the quadratic equation (either by differentiation or completing the square) and seeing that the last value at the end of the simplified equation is "-7".i think i get it now.

Reply 122

lollipop

U want it to be the MINIMUM. If 3(x-2)^2, say equalled 2. Then...+2-7, only gives -5

We're not saying 3(x-2)^2 = 2, we're saying x =2! I think me and Bhaal are going to implode pretty soon....

Reply 123

king of swords

Unregistered

fantastico!!!! the minimum value, is the minimum value that the y coordinate can be, when we have found the value of x from solving that simple linear equation...i get it!!! and we find this minimum value (y co-ordinate), by solving the quadratic equation (either by differentiation or completing the square) and seeing that the last value at the end of the simplified equation is "-7".i think i get it now.

Good stuff (y)

Reply 124

lollipop

LMAO please calm down

come on now, lets call it quits. Its 12, and we really ought to be in bed sleeping. Instead we are debating over a maths question......lol, I never though this day would come....

Reply 125

theone

We're not saying 3(x-2)^2 = 2, we're saying x =2! I think me and Bhaal are going to implode pretty soon....

'I think I deserve some apprecition, so any REP would be fine'

*blows up into a million pieces*

Reply 126

Unregistered

yes i know, for when x = 2, the minimum value (the y-coordinate this takes) = - 7. using these 2 points, we can then draw the vertex, correct? and if we double differenciate, we can see if its a min or max turning point aswell, correct?

Reply 127

lollipop

LMAO please calm down

come on now, lets call it quits. Its 12, and we really ought to be in bed sleeping. Instead we are debating over a maths question......lol, I never though this day would come....

I'm sorry but this must be the 20th odd time i've explained how to complete the square, and anyway who doesn't get it after that many times just isn't paying enough attention.

Reply 128

king of swords

lollipop

LMAO please calm down

come on now, lets call it quits. Its 12, and we really ought to be in bed sleeping. Instead we are debating over a maths question......lol, I never though this day would come....

Lol!!! I agree, I'm off now, I'll see y'all later.

Reply 129

lollipop

i never sed x didnt = 2. I also sed that x=2 y=-7

lol

Reply 130

lollipop

if we expand he equation

3(x-2)^2 -7
3(x^2 - 4x + 4) -7
3x^2 - 12x + 12 -7
3x^2 -12x +5

Ooh, does that not eqaul the original equation??? I think it does! lol

no, cause you cant have the seven outside like it is.

Reply 131

lollipop

i never sed x didnt = 2. I also sed that x=2 y=-7

lol

thought we we're calling it quits?

Reply 132

Bhaal85

no, cause you cant have the seven outside like it is.

it must be conatined in the bracket like 'a((x-p)^2+q)'

Reply 133

Unregistered

i know how to complete the square and differenciate, i just wanted to clarify the terminology, and you have. i understnad what "minimum value" and "value of x which gives this minimum value" and "minimum/maximum turning point" mean....................ok? happy now?

Reply 134

lollipop

We are

Please calm down Bhaal85...sorry if i caused any aggro.

Reply 135

Unregistered

i know how to complete the square and differenciate, i just wanted to clarify the terminology, and you have. i understnad what "minimum value" and "value of x which gives this minimum value" and "minimum/maximum turning point" mean....................ok? happy now?

I think the question is are you happy now?

Reply 136