Did anyone get how to prove Q23 (second last question, triangles with ratios for side lengths)? It’s the only one I was stumped on, and it’s REALLY bothering me.

Lmao I assigned values to the biggest side and used the ratio of the triangles to actually find the areas. Took so long but I did manage to prove it I think?

I used 4 as the bottom of the biggest triangle, so then I got 2sqrt2 over 3 for the small triangle, 16sqrt2 over 3 for the middle trapezium and 18sqrt2 for the big one, which simplifies down to 1: 8: 27

(edited 10 months ago)

Reply 45

user01906002

Original post by williamdouglas

did you get 120 for the histogram question?

I did

Reply 46

jack_ray13

Original post by yx3003

you had to talk about scale factor and how area of a trapezium is area of big triangle take away area of small triangle

Oh I did that hopefully I get some marks

Reply 47

Caotica

Original post by williamdouglas

did everyone get 4 as the integer for last question?

Yes, this is the right answer

Reply 48

joelymoley1

what did everyone get for Q5? it was the “triangle is 10cm2 more than rectangle area” thing

Reply 49

user01906002

Original post by joelymoley1

what did everyone get for Q5? it was the “triangle is 10cm2 more than rectangle area” thing

I got 1.25 but no idea if it was right

Reply 50

Munachieziefula

Original post by user01906002

I did

i got 104

Reply 51

williamdouglas

Original post by user01906002

I got 1.25 but no idea if it was right

i got that

Reply 52

Isaac L

For q23 I labelled the sides as x 2x and 3x on the right and y 2y and 3y on the left calculated the area for each side using 1/2abSinC then when I get to the ratio I cancel out the xySinC.

Reply 53

Caotica

Original post by williamdouglas

i got that

Same

Reply 54

Isaac L

Original post by williamdouglas

did everyone get 4 as the integer for last question?

Yes

Reply 55

yx3003

Original post by Bksa

Can anyone explain the ratio proof one? I got to it but I had to switch some values ;-;

you had to make c = in both sides so times the first by 7 and the second by 2 and you had to make what c = the same so times the first by 21 and the second by 20 then you get 14a:20b:35c = 126:500:525 and you work out each value a = 9 b= 25 and c =15 then 9=25 = 34 and 25+15 = 40 that gives ratio of 34:40 witch can be simplified to 17:20