Heeeeelp I'm stuck again PLS

heyy, stupid question, but if I have 9+2x on the numerator of my second fraction, and my second fraction is negative, do I do a or b.
let's assume my first fraction numerator is a, and both denominators are the same

a) a/2 - (9+2x)/2 = ( a -9 + 2x ) /2
b) (a - 9 - 2x ) /2

Is the whole of the second numerator made negative if it has more than 1 term? I swear it is, but you know when you just start thinking too hard and then you undo your understanding? Yeah, oops

You should use brackets on the numerator to make it clear and avoid mistakes:

$\displaystyle \frac{a}{2} - \frac{9+2x}{2} = \frac{a-(9+2x)}{2}$

$a-(9+2x) = a-9-2x$

So b) is the right answer.

Thank youuuu, I know it's such a basic question but I genuinely thought about it for 3 minutes and completely lost all my brain cells