The Student Room Group
Work out the moles of Iron with mass=moles x mr

From this work out the number of moles of Hydrogen

Put the number of moles into pV=nRT
Reply 2
You need to work out at the end of the reaction (assuming 100% yield) how much hydrogen there is.

You then use the fact that 1 mole of gas takes up 22.4 dm^3 of space, regardless of what the gas is.

EDIT: This is a standard result from pV = nRT
Reply 3
3 moles of iron forms 4 moles of hydrogen gas.
can you work from there?
Reply 4
Dogkicker91
Work out the moles of Iron with mass=moles x mr

From this work out the number of moles of Hydrogen

Put the number of moles into pV=nRT



i get 59201.24 L

does it look right??
Reply 5
0zero0
i get 59201.24 L

does it look right??


hmmmm

A litre isn't eactly a standard unit for quoting volumes. Stick with Pa.

EDIT: dm^3.
Reply 6
DeanK2
hmmmm

A litre isn't eactly a standard unit for quoting volumes. Stick with Pa.


does the answer look right though?
im not sure as im doing such questions for the first time!
Reply 7
what is the mr of iron?
Reply 8
DeanK2
what is the mr of iron?


55.8
When quoting your volumes in chemistry, always always use dm^3
Reply 10
because iron there is 3 moles would it be 100 / 55.8 or (55.8 x 3) ?

that's the part i'm stuck on. other than that you'd find the number of moles using:

n = mass / Ar
n = 100 / 55.8 (i think)

= 1.792

then convert your units into SI units
100kPa = 100000 Pa.
298 K is fine
then use your gas equation to find volume

nRT/p

substitute in your numbers

1.792 x 8.31 x 298
/
100000

work that out...

unless, like I said I've gone TOTALLY wrong due to it being 3 moles of Iron..could anyone clear this up...

other than that i'm positive the working out is right....does that help?

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