it's from the CGP book. basically, V = 160 E = 120kJ t = 60s and we need to find the current (I), flowing through the electric heater. the answer is 12.5A
does anyone have any ideas on how to connect I with another variable given here?
Power (Watts) is Energy (Joules) per unit of time (seconds)
Power is also PD (Volts) multiplied by current (Amps)
Hang on a sec. If P=Et (according to formula sheet), you're saying that IV=Et (I think) so 120/160 x 60 x10^3 would be the same as 0.75 x 60 x 10^3, which is 45 x 10^3 A. This isn't an option.