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# Translations of graphs need help Tweet

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1. Translations of graphs need help
Can someone reflect these in the y-axis please?

y=2x^3+x^2-5x+1

y=3sin(x)

And can someone stretch these parallel to the x axis please

y=x^2 by scale factor 3 parallel to the x-axis

y=x^2-4x+1 by scale factor 0.5 parallel to the x axis

y=3sin(x) by scale factor 1/5 parallel to the x-axis

45 minutes ago
- 4 days left to answer.
2. Re: Translations of graphs need help
A reflection in the y axis is to swap around the positive and negative sides of the x axis.

To stretch f(x) by a factor of a along the x axis, you need f(x) to come at a*x, hence you get the stretch being f(x/a). The division by a means x has to be a times as large to get the same value of f.
3. Re: Translations of graphs need help
agree to that ^^^^^
4. Re: Translations of graphs need help
(Original post by iceman95)
Can someone reflect these in the y-axis please?

y=2x^3+x^2-5x+1

y=3sin(x)

And can someone stretch these parallel to the x axis please

y=x^2 by scale factor 3 parallel to the x-axis

y=x^2-4x+1 by scale factor 0.5 parallel to the x axis

y=3sin(x) by scale factor 1/5 parallel to the x-axis

45 minutes ago
- 4 days left to answer.
Generally:
let
THen
Reflection in the y-axis:
Reflection in the x-axis:
Translating by 'a' parallel to the x:
Translating by 'a' parallel to the y:
Streching by scale factor 'a' parallel to x:
Streching by scale factor 'a' parallel to y:

F.e for 2nd

for 4th
5. Re: Translations of graphs need help
(Original post by ztibor)
Generally:
let
THen
Reflection in the y-axis:
Reflection in the x-axis:
Translating by 'a' parallel to the x:
Translating by 'a' parallel to the y:
Streching by scale factor 'a' parallel to x:
Streching by scale factor 'a' parallel to y:

F.e for 2nd

for 4th
How can I reflect y=2x^3+x^2-5x+1 into the y-axis?