OCR C2 Exam May 18th 2012

Reply 240

kenann

Original post by samjj8

Also for the one where you had to find the value of x... I got something like X^3 = 64/27 ... so x = third root 64/3?

cubert(64/27) = 4/3

therefore x = 4/3

Reply 241

emtv

Original post by samjj8

Overall, it was an OK paper. The last question, I couldn't find the range of y? I know that the value has to be between 1 and -1.
So I put y> 2 for some extremely strange reason. Because 1-1 = 0 and you can't have 0 on the bottom. Got the 5 marker correct! :biggrin:

Also for the one where you had to find the value of x... I got something like X^3 = 64/27 ... so x = third root 64/3?

When I subbed it into X, it was correct... but I have never left something as a third root in standard form. It wanted the exact answer??

For the Trig graph, I just did the same thing for part 2 for part 1. Completely forgot what I needed to do for obtuse angles.

I got 0.5 < y < 2 as when you sub them in you get -1 and 1.

Cube root of 64/27 = 4/3 which is an exact answer I think?

I could be wrong with these 2 though!

(edited 11 years ago)

Reply 242

kelvinkw

overall its an easy paper. probably dropped 1 mark .on the obtuse angle question

Reply 243

abarlas123

What did everyone out for f(x) and g(x) where it asked to factories fully, i couldn't do it coz i kept on getting root of negative number for the quadratic formula

Reply 244

samjj8

1

Original post by kenann

cubert(64/27) = 4/3

therefore x = 4/3

Yeh, for some reason I got a decimal, I definately did the LOGS right, and when I subbed my answer back into the question, it worked... :\ Can anyone remember the question?

Reply 245

J.C

I got the obtuse part wrong so -3. Although I know how to do it now... us the identity sin^2 + cos^2=1 so cos^2x=1- (3/7)^2 and solve to sin^2x to get root40/7 I think.

I spent 40 mins looking at the questions using triangles, graphs...just didn't get the "Eureka" moment to use a simple trig identity. *sigh*

Reply 246

matty b

Original post by samjj8

Overall, it was an OK paper. The last question, I couldn't find the range of y? I know that the value has to be between 1 and -1.
So I put y> 2 for some extremely strange reason. Because 1-1 = 0 and you can't have 0 on the bottom. Got the 5 marker correct! :biggrin:

.

Almost there. 0.5>y>2

the equation requires the abs. value. This means log2(y) can be -1. So y is more than 0.5. (2 to the minus 1 is a half)

Reply 247

Katherine1

I found that awful! So much harder than past papers, and I didn't finish a few questions because I ran out of time... For me, that was my worst exam ever eughhhhhhhhh I'm so annoyed at myself!

Reply 248

needtosucceed=)

10

Original post by abarlas123

What did everyone out for f(x) and g(x) where it asked to factories fully, i couldn't do it coz i kept on getting root of negative number for the quadratic formula

the two factors were like (x-2) (x-3) or something like that? those were the two number, cant remember which way round the signs were though

Reply 249

Pride

21

unbelievable.

Those tan/cos/sin questions were unbelievable. I just had no idea how to convert them into an exact figure.

Reply 250

J.C

do people think 72 will do 100 UMS or what?

If all goes well I get 69/72, what UMS do people think that might be. I was hoping for full marks tbh but the obtuse questions got me.

Reply 251

matty b

Original post by Pride

unbelievable.

Those tan/cos/sin questions were unbelievable. I just had no idea how to convert them into an exact figure.

agreed

Reply 252

samjj8

1

Original post by abarlas123

What did everyone out for f(x) and g(x) where it asked to factories fully, i couldn't do it coz i kept on getting root of negative number for the quadratic formula

(x-3)(x+1)(x-2)

I am not sure about the pluses and minuses, I can't remember which way round they were. Might have been x+3

Though the ones which f(x) share a common factor with is (x-3)(x+2)

Reply 253

J.C

Original post by Pride

unbelievable.

Those tan/cos/sin questions were unbelievable. I just had no idea how to convert them into an exact figure.

Use a right angle triangle for the 1st part and the sin^2 + cos^2=1 identity for the 2nd I believe. Got the 2nd part wrong though as I didn't spot that.

Reply 254

Pride

21

Original post by J.C

I got the obtuse part wrong so -3. Although I know how to do it now... us the identity sin^2 + cos^2=1 so cos^2x=1- (3/7)^2 and solve to sin^2x to get root40/7 I think.

I spent 40 mins looking at the questions using triangles, graphs...just didn't get the "Eureka" moment to use a simple trig identity. *sigh*

Original post by matty b

agreed

same, I asked a maths teacher and he said that was easy, shoulda used an identity... damn I was drawing graphs, SATC grids, I just couldn't see it...

Reply 255

kenann

Original post by J.C

do people think 72 will do 100 UMS or what?

If all goes well I get 69/72, what UMS do people think that might be. I was hoping for full marks tbh but the obtuse questions got me.

yeah, exactly this. i know exactly how to do them now which is what frustrates me most.

and also instead of 0<y<2 and y>0, i just wrote 'y<2', i'll have to wait for mr. m to see how many marks i've dropped in total

Reply 256

JASApplications

Overall I didn't think it was too bad. I made a few careless errors which will cost me a few marks and then messed up the alpha, beta and gamma question. (Hadn't a clue how to do it!).

Did everyone get 0.67 for the last question and then x=2 and x=-3 for the f(x) and g(x) big question?

Reply 257

J.C

Original post by Pride

same, I asked a maths teacher and he said that was easy, shoulda used an identity... damn I was drawing graphs, SATC grids, I just couldn't see it...

Yeah now that I see it, it's easy. Just annoyed as I think I may have got full marks If I hadn't got that wrong.

Reply 258

Seanyboy57

Original post by JASApplications

Did everyone get 0.67 for the last question and then x=2 and x=-3 for the f(x) and g(x) big question?

Last question needed to be an exact value - 2/3

Reply 259

J.C

Original post by kenann

yeah, exactly this. i know exactly how to do them now which is what frustrates me most.

and also instead of 0<y<2 and y>0, i just wrote 'y<2', i'll have to wait for mr. m to see how many marks i've dropped in total

Yeah and I got told how to do it afterwards and was so annoyed, really easy tbh, just didn't think to use an identity.

OCR C2 Exam May 18th 2012

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