\displaystyle [br]\begin{align*}\ln(x+3) + \ln(x-1) = 0 &\iff \ln(x+3)(x-1) = 0 \\ &\iff (x+3)(x-1) = e^0 = 1 \\ &\iff x^2 -x + 3x - 3 = 1 \\ & \iff x^2 +2x -4 = 0 \\ &\iff \cdots\end{align*}
\displaystyle [br]\begin{align*}\ln(x+3) + \ln(x-1) = 0 &\iff \ln(x+3)(x-1) = 0 \\ &\iff (x+3)(x-1) = e^0 = 1 \\ &\iff x^2 -x + 3x - 1 = 1 \\ & \iff x^2 +2x -2 = 0 \\ &\iff \cdots\end{align*}
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