\displaystyle[br]\begin{equation*} \frac{\frac{2}{\tan \theta}}{\frac{1}{\tan^2 \theta} - 1} = \cdots = \frac{2 \tan \theta}{1 - \tan^2 \theta}\end{equation*}
\displaystyle[br]\begin{equation*} \frac{\frac{2}{\tan \theta}}{\frac{1}{\tan^2 \theta} - 1} = \cdots = \frac{2 \tan \theta}{1 - \tan^2 \theta}\end{equation*}
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Did Cambridge maths students find maths and further maths a level very easy?Last reply 2 weeks ago
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Did Cambridge maths students find maths and further maths a level very easy?Last reply 2 weeks ago
Edexcel A Level Mathematics Paper 2 unofficial mark scheme correct me if wrong71