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AQA CHEM4 discussion/unofficial mark scheme

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I actually thought I was going to do well in this paper but no :angry: screw you AQA
Reply 21
Yeah they will have been step 3 and 4 i just couldn't remember the numbering in the question
Reply 22
Could you not write KCN dissolved in ethanol?


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Original post by mgill17
So I think this was Question 8

It asked how to basically get an alcohol from an ester
I basically described Base Hydrolysis...so using NaOH and heating under reflux. Then distilling it off.
I guess you could've described Acid Hydrolysis too and there's another one some people at my college put but I can't remember that one.

The structure of S was the same bromoalkane it gave you (was it 2-bromobutane? I can't remember) but you swapped the Br for a Nitrile group

Step 1
Reagent was KCN
Conditions was aqueous

Step 2
Reagent was LiAlH4
Conditions was dissolved in ether

---I think that was it someone correct me if I'm wrong------


it should be ethanol and water mixture to convert haloalkane to nitrile isn`t it?
Reply 24
Original post by DDan123
Could you not write KCN dissolved in ethanol?


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I said KCN in ethanolic conditions, I think they may accept that
Nah, that NMR one lmao. I knew NMR would haunt me, but that was just... ugh.

I'm so sad that I'm not sad. - I don't even have time to mourn bc maths tomorrow which I cba for now. ):

Well, I guess we still have unit 5.
Reply 26
Original post by iselhong
it should be ethanol and water mixture to convert haloalkane to nitrile isn`t it?


Oops yeah. I meant ethanolic that's what I put in the paper. Idk why I put aqueous there..I'll change it!
Original post by Anon_98
Nah, that NMR one lmao. I knew NMR would haunt me, but that was just... ugh.

I'm so sad that I'm not sad. - I don't even have time to mourn bc maths tomorrow which I cba for now. ):

Well, I guess we still have unit 5.


The entire paper was horrible and ugh imho

Best of luck with your maths, I hope it isn't as bad as this paper was.

You still have Unit 5, I already did it and got a B in it, Unit 5 is easier
Such a horrible paper!!! The questions were so difficult and it was far too long! I ran out of time 😥
Reaction orders : A-1
B-2
Reply 30
Just so gutted. Not sure if I got an A and the Empa wasn't great either. Think I need like full UMS unit 5 lool


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Original post by logicmaryam
Heey guys, I think we can all agree this paper was one of the hardest CHEM4 papers ever.
We'll discuss the answers and compile an unofficial mark scheme. Post your answers here!

Q1 20 marks
a) Ethanoic acid in water
CH3COOH CH3COO- + H+ (1)
b) Ethanoic acid as base with HNO3
HNO3 + CH3COOH = CH3CHOOH2+ + NO3- (1)
c) pH of acid? 2.08 (3)
d) pH when alkali added to acid 2.32 (4)
e) [salt]/[acid] = 3.33 (3)

why is chloroethanoic acid stronger than ethanoic acid? (2)
Chlorine is more electronegative so will withdraw electrons and weaken the O-H bond so H is lost more easily


I got CH3COOH + H2O CH3COO- + H3O+ bc it said reaction with water?
I agree.

Thank you + I don't think it'll be, no. Or at least I v much hope not bc it's one of the 'easy' resits.

Oh, nice, I see! Yeah, I also find unit 5 a whole lot better. :'3 Good luck with your next exam too.
Original post by shellypatel2
I got CH3COOH + H2O CH3COO- + H3O+ bc it said reaction with water?


I put this too, I'm not sure though :smile:

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Original post by iselhong
Did anyone work out the last question ? i ran out time to finish the explain bit.
i did something like (HO)CH2CH2C(CH3)2CH2(OH)


I think it's CH3 O C(CH3)2 CH2CH2 OH
Anybody else get this?...

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Original post by MuslamicJihad
The nmr at the end was (I think): CH3OCH2CH2C(CH3)2OH

This was what I got and it was the most common mistake on the last question. That is a tertiary alcohol and the question clearly said that the compound could be reduced by potassium dichromate which means that it cannot have been a tertiary alcohol.
That was officially the worst paper ever and Aqa were very harsh, why did they have to change the syllabus on our year and therefore because we're the final year sitting it they decided to make it memorable. Here's to hopping the grade boundaries are rock bottom. :redface:
Original post by RedNebula
I think it's CH3 O C(CH3)2 CH2CH2 OH
Anybody else get this?...

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Yessss mate same here
Reply 38
what did everyone get for Q3f? it was about lidocaine hydrochloride
Original post by logicmaryam
Heey guys, I think we can all agree this paper was one of the hardest CHEM4 papers ever.
We'll discuss the answers and compile an unofficial mark scheme. Post your answers here!

Q1 20 marks
a) Ethanoic acid in water
CH3COOH CH3COO- + H+ (1)
b) Ethanoic acid as base with HNO3
HNO3 + CH3COOH = CH3CHOOH2+ + NO3- (1)
c) pH of acid? 2.08 (3)
d) pH when alkali added to acid 2.32 (4)
e) [salt]/[acid] = 3.33 (3)

why is chloroethanoic acid stronger than ethanoic acid? (2)
Chlorine is more electronegative so will withdraw electrons and weaken the O-H bond so H is lost more easily


I swear e is wrong, I got 1.2 instead of 3.33

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