It asked how to basically get an alcohol from an ester I basically described Base Hydrolysis...so using NaOH and heating under reflux. Then distilling it off. I guess you could've described Acid Hydrolysis too and there's another one some people at my college put but I can't remember that one.
The structure of S was the same bromoalkane it gave you (was it 2-bromobutane? I can't remember) but you swapped the Br for a Nitrile group
Step 1 Reagent was KCN Conditions was aqueous
Step 2 Reagent was LiAlH4 Conditions was dissolved in ether
---I think that was it someone correct me if I'm wrong------
it should be ethanol and water mixture to convert haloalkane to nitrile isn`t it?
Heey guys, I think we can all agree this paper was one of the hardest CHEM4 papers ever. We'll discuss the answers and compile an unofficial mark scheme. Post your answers here!
Q1 20 marks a) Ethanoic acid in water CH3COOH ⇌ CH3COO- + H+ (1) b) Ethanoic acid as base with HNO3 HNO3 + CH3COOH = CH3CHOOH2+ + NO3- (1) c) pH of acid? 2.08 (3) d) pH when alkali added to acid 2.32 (4) e) [salt]/[acid] = 3.33 (3)
why is chloroethanoic acid stronger than ethanoic acid? (2) Chlorine is more electronegative so will withdraw electrons and weaken the O-H bond so H is lost more easily
I got CH3COOH + H2O ⇌ CH3COO- + H3O+ bc it said reaction with water?
The nmr at the end was (I think): CH3OCH2CH2C(CH3)2OH
This was what I got and it was the most common mistake on the last question. That is a tertiary alcohol and the question clearly said that the compound could be reduced by potassium dichromate which means that it cannot have been a tertiary alcohol.
That was officially the worst paper ever and Aqa were very harsh, why did they have to change the syllabus on our year and therefore because we're the final year sitting it they decided to make it memorable. Here's to hopping the grade boundaries are rock bottom.
Heey guys, I think we can all agree this paper was one of the hardest CHEM4 papers ever. We'll discuss the answers and compile an unofficial mark scheme. Post your answers here!
Q1 20 marks a) Ethanoic acid in water CH3COOH ⇌ CH3COO- + H+ (1) b) Ethanoic acid as base with HNO3 HNO3 + CH3COOH = CH3CHOOH2+ + NO3- (1) c) pH of acid? 2.08 (3) d) pH when alkali added to acid 2.32 (4) e) [salt]/[acid] = 3.33 (3)
why is chloroethanoic acid stronger than ethanoic acid? (2) Chlorine is more electronegative so will withdraw electrons and weaken the O-H bond so H is lost more easily