AQA MM1B - Mechanics 1 -Tuesday 21st June 2016

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Reply 100

reuel

Question 7 well most of it

Reply 101

Matt309

Exactly, I got two value for t, t=5 AND t=25.k assumed one of them was correct so I solved for the displacement using t=5 and 25 and got two different answers, when t=25 I got around the 330m areas and when t=5 I got around 80m(i cant remember exact value but I think the correct answer was around 80m between them)

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Reply 102

LiesandAlibis

How do you guys think it was compared to previous years?
Any thoughts on grade boundaries/full UMS?

Reply 103

Minnie1998

Original post by reuel

Question 7 well most of it

i got the same!!

Reply 104

123thatmathsyute

This paper was tooo easy defo 70 for an A, the 10 mark was joke clocked it in 3 minutes had 35 minutes to check answers. WOOOOAHHH, some of you man are **** cambizzy here i come gunna celebrate 100 ums with some cheeky nandos see ya ******s

Reply 105

Pinocchiolewis

These are the answer that me and my friends got, let me know if you can't read it/if any of them are wrong 😊

Reply 106

09MHall

Original post by RorMur2992

I got 106m for the 10 marker, anyone else?

Yes I got this too

Reply 107

Matt309

U got Identical answers to you

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Reply 108

smitherito

Original post by matt5822

But the i components were different

Surely parallel means in the same plane. If the I and j equated each other they would be travelling in the same line not parallel?

Reply 109

con.brown

No air resistance for the assumption is correct and valid, as implying it is a particle means its surface area is negligible and therefore is not affected by the effect of drag.

Reply 110

LiesandAlibis

Original post by Minnie1998

i got the same!!

Surely you cannot keep time as the same?
It would take a different amount of time to reach the back of the net, no?

Reply 111

jtebbbs

Original post by reuel

Question 7 well most of it

You can't use 1.76 for the time in the second part, the horizontal distance travelled has changed so the time of flight will also have changed.

Reply 112

Timotheus

How many marks would I lose in Q8 would you guys think? I got T = 12 but i calculated the difference of speed but not distance

Reply 113

Chickenslayer69

For Q8 I only did it for the i components and got 80.5m with t=5, but I think people who did it for j components got t=12 and 106m, which is why there are 2 answers many are getting. Not sure which is right.

Reply 114

jtebbbs

Original post by con.brown

No air resistance for the assumption is correct and valid, as implying it is a particle means its surface area is negligible and therefore is not affected by the effect of drag.

The question definitely said "model the ball as a particle with no air resistance" so whilst that's correct, it wouldn't be a valid answer. I don't know what the right answer is, but I put that you can ignore the ball's tendency to rotate, cause that's come up as an advantage before. Also, in real life, if you put a spin on the ball it changes its motion

Reply 115

MLW12345

ah finding the values of P & q wasn't it just comparing I + J components separately?

Reply 116

Examguy123

Original post by LiesandAlibis

How do you guys think it was compared to previous years?
Any thoughts on grade boundaries/full UMS?

I think it was comparable to june 13 paper in which case the marks needed for an A were 53

Reply 117

Matt309

This is what I thought which Is why I couldn't figure it out

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Reply 118

Adam_98

Original post by smartsy

My answers (might have misremembered some, and others are probably wrong):
1) 15 kg
2) p = 14, q = 17
3) 9 degrees
4) V = 12, bearing = 008
5) Max heigh 1.2 m (can't really remember)
6) 43.8 N
7) Velocity around 13, modelling as particle means air resistance can be ignored)
8) I got up to finding t = 5 and t = 25, but then did a load of meaningless BS and got the wrong answer around 28 lol.