Hey bro, thanks for replying. I'm relatively new to this chapter. May i know how do you differentiate y=f(x), and x=e^u to prove dy/du? I need little of guidelines regarding to that. Thank you mate. Cheers
Hey bro, thanks for replying. I'm relatively new to this chapter. May i know how do you differentiate y=f(x), and x=e^u to prove dy/du? I need little of guidelines regarding to that. Thank you mate. Cheers
Hey bro, thanks for replying. I'm relatively new to this chapter. May i know how do you differentiate y=f(x), and x=e^u to prove dy/du? I need little of guidelines regarding to that. Thank you mate. Cheers
You know that dud(eu)=eu right?
You want dxdy and by the chain rule that is dudy×dxdu as f(g(x))′=f′(g(x))×g′(x)
Also dxdy=dydx1 Use dy/dx in terms of e^u and show what the question asks for.
@NotNotBatman@RDKGames Thank you for your help. I misunderstood the question as i take function of as f(x) . Thank you for your time once again. appreciated it
@NotNotBatman@RDKGames Thank you for your help. I misunderstood the question as i take function of as f(x) . Thank you for your time once again. appreciated it