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Who wants to help?
Bonjour!
I Stick in calculation of particle fraction integral. So, who wants to help me?
Here we go,
I'll write integral sample as S oSx ....means from o to x, DEAL!
Too weird huh, but why not?
If these formulas not clear I'll post a document
Alors,
oSx n/a-x +q/b-x dx = kt
where n= 1/b-a q= 1/a-b
0Sx 1/(b-a)/a-x + 1/(a-b) /b-x dx = kt
0Sx 1/(b-a)(a-x) + 1/(a-b)(b-x) dx =kt
1/b-a oSx 1/a-x dx + 1/a-b oSx 1/b-x dx = kt
1/b-a Ln a-x - Ln a + 1/b-a Ln b-x - Ln b =kt
1/b-a Ln a-x/a + 1/a-b Ln b-x /b =kt
Now, I want to make the last formula look like
1/a-b Ln b (a-x)/ a (b-x) = kt
And turns to:
1/a-b Ln (a-x)/(b-x) = kt + 1/ a-b Ln a/b
How can I make it? I know that I'm so close to the end. Please help me
Merci.
I Stick in calculation of particle fraction integral. So, who wants to help me?
Here we go,
I'll write integral sample as S oSx ....means from o to x, DEAL!
Too weird huh, but why not?
If these formulas not clear I'll post a document
Alors,
oSx n/a-x +q/b-x dx = kt
where n= 1/b-a q= 1/a-b
0Sx 1/(b-a)/a-x + 1/(a-b) /b-x dx = kt
0Sx 1/(b-a)(a-x) + 1/(a-b)(b-x) dx =kt
1/b-a oSx 1/a-x dx + 1/a-b oSx 1/b-x dx = kt
1/b-a Ln a-x - Ln a + 1/b-a Ln b-x - Ln b =kt
1/b-a Ln a-x/a + 1/a-b Ln b-x /b =kt
Now, I want to make the last formula look like
1/a-b Ln b (a-x)/ a (b-x) = kt
And turns to:
1/a-b Ln (a-x)/(b-x) = kt + 1/ a-b Ln a/b
How can I make it? I know that I'm so close to the end. Please help me
Merci.
Scroll to see replies
je ne comprends pas
erm could you post a document...all that is confusing!
sorry can't open .docx
this may be useful: http://www.thestudentroom.co.uk/wiki/LaTex
this may be useful: http://www.thestudentroom.co.uk/wiki/LaTex
2^1/2
I'll deal with it in a minute.
~$0xna11.doc
Now what?
Now what?
Hanouf
~$0xna11.doc
Now what?
Now what?
ÇÈæ ãäÕæÑ ' ( H E F 5 H 1
C o u r i e r N e w
C o u r i e r N e w
C o u r i e r N e w Hÿ-
that's useful - would you like help with this question or not?
Hanouf
0xna.doc
one more time
one more time
sorry took me a while to work put why it wouldn't work.
in your document have a look at step (5)
remember the '-' sign here.
then when you get to the end take out a factor of 1/(a-b), (as it is what the answer does)
can you see how to make 1/(b-a) take that form?
Spoiler
then just use log laws
hope that helps, i'm off to bed
steve2005
I can now read your document BUT am puzzled as to where the t comes from.
I assume the k is a constant and would have expected it to be followed by x and not t.
I assume the k is a constant and would have expected it to be followed by x and not t.
i doubt it matters, whatever the question is it has two constants multiplied by each other (i don't know the context so one may be another variable)
but the question is fine, if you just accept it.
2^1/2
sorry took me a while to work put why it wouldn't work.
in your document have a look at step (5)
remember the '-' sign here.
then when you get to the end take out a factor of 1/(a-b), (as it is what the answer does)
can you see how to make 1/(b-a) take that form?
then just use log laws
hope that helps, i'm off to bed
in your document have a look at step (5)
remember the '-' sign here.
then when you get to the end take out a factor of 1/(a-b), (as it is what the answer does)
can you see how to make 1/(b-a) take that form?
Spoiler
then just use log laws
hope that helps, i'm off to bed
Merci Infiniment!
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