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Further Pure Help

1.) Using integration to prove the curved surface area of a cylinder has the equation

A=2 \pi r h

2.) if

(\frac{3iz+5}{2iz+7})^4

=1 find z

3.) How do you find the equation of having roots

\frac{ab}{a^2+b^2}

... The equation having roots

a, b, \gamma

x^3+ax+b=0

if you wanna know....( from the root I worked out until

\frac{ab\gamma+U \gamma^3}{a^2+b^2+\gamma^2}=U\gamma

then I got stuck and was pulling my hair out T.T)

This was my yesterday trials paper.. so no answer has been given out yet :wink:

Reply 1

rnd

1) That's circumference x height. This only gives the curved surface area.

2) Something missing here.

3) Don't feel like doing this one now :wink:

Reply 2

manthew

rnd

1) That's circumference x height. This only gives the curved surface area.

2) Something missing here.

3) Don't feel like doing this one now :wink:

Fixed... >.< I'm terribly sorry, was rushing to a good shower =P

anyone

1) You need

\displaystyle\int_0^h 2\pi y \sqrt{1+(\frac{dy}{dx})^2 }dx

y is the constant r and dy/dx=0.

\displaystyle 2\pi r \int_0^h \sqrt{1+0^2 }dx

I'll leave the rest to you.

2) Take the 4th root of each side. The possibilities on the RHS are 1,-1,i and -i, (the fourth roots of 1)

Solve for each case.

3) Still not in the mood for that one :biggrin:

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