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OCR MEI - CORE 1 on 18th May 2011 (tomorrow)

Hey guys

will someone please be a dear and help me with a few questions?

June 2007, Section A
q 9ii.
q 10ii

January 11, Section A
7i
Express 81/(square root)3 in the form 3^k

Thankyou :smile:

Scroll to see replies

Reply 1

TimetoSucceed

81/sqrt3 = 81/3^1/2

81 = 3^4 right?

so you essentially have 3^4 / 3^1/2, so you take them away and get 3^3.5

Reply 2

TimetoSucceed

Vector of 2,0

so x is now turned into (x-2)

original equation is x^2-4

so it is now (x-2)^2 - 4

Reply 3

TimetoSucceed

factorise you get

(2x - 7)(x+3)

x = -3 or 7/2

height is x+1, height cannot be negative, so 7/2+1 = 9/2 = 4.5

base is 2x-3, cannot be negative, so 14/2-6/2 = 8/2 = 4

Reply 4

NH2010

hey
whats likely to come up, im seriously ****ting myself

Reply 5

SugarLips.

Original post by NH2010

hey
whats likely to come up, im seriously ****ting myself

You can't guess what's gonna come up, past papers are reaally similar
I'm so scared, I can't do section B it actually makes me wanna cry!

Reply 6

SugarLips.

Original post by TimetoSucceed

81/sqrt3 = 81/3^1/2

81 = 3^4 right?

so you essentially have 3^4 / 3^1/2, so you take them away and get 3^3.5

Can you explain that again, I'm lost.. where does the half come from?

Reply 7

SugarLips.

Original post by TimetoSucceed

Vector of 2,0

so x is now turned into (x-2)

original equation is x^2-4

so it is now (x-2)^2 - 4

So you just put it into the backet?
what would you do if the vector was 0,2 ?

Reply 8

SugarLips.

Original post by TimetoSucceed

factorise you get

(2x - 7)(x+3)

x = -3 or 7/2

height is x+1, height cannot be negative, so 7/2+1 = 9/2 = 4.5

base is 2x-3, cannot be negative, so 14/2-6/2 = 8/2 = 4

say for example, both x's were positive which would you substitute?

& THANK YOU SO MUCH BTWW!

Reply 9

levantine

is there a difference between ocr mei core 1 and just normal ocr core1

Reply 10

deltaforce456

yes their is, OCR MEI is different to just OCR.

Reply 11

deltaforce456

Original post by SugarLips.

You can't guess what's gonna come up, past papers are reaally similar
I'm so scared, I can't do section B it actually makes me wanna cry!

I JUST WANT TOMORROW TO FLY BY!!! :rolleyes:

Reply 12

Woffles

Don't worry guys, you'll be fine! If anything makes tomorrow go badly, it will be nerves! So don't be nervous :biggrin:

Reply 13

xChelsea

Original post by SugarLips.

Can you explain that again, I'm lost.. where does the half come from?

The square root of a number is the same as that number to the power of a half.
e.g. Squareroot of 9 is the same as 9^1/2 which both equal 3.

Don't know if that helped.

Reply 14

xChelsea

Original post by SugarLips.

So you just put it into the backet?
what would you do if the vector was 0,2 ?

If the vector was 0,2
The original equation y = x^2 - 4
Changes to y = x^2 - 2

Reply 15

campainr

Original post by deltaforce456

I JUST WANT TOMORROW TO FLY BY!!! :rolleyes:

wrong thread

(edited 12 years ago)

Reply 16

iFreak

I have this exam tomorrow D: I haven't revised at all - here's hoping for a nice easy paper...

Reply 17

Porkk

Same but then easiness = higher boundaries...

Reply 18

ap12345678910

how did we all find it ?

Reply 19

jahangir75

Found the second question in section B a nightmare :mad:

, messed the intersection question up in the first bit of section B and the discriminant part in section A. But beside from those, i fort the paper was pretty easy. The circle question was a piece of cake :smile:

. Prediction: 60/72