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OCR Chemistry A F325 Equilibria, Energetics and Elements Wed 13 June 2012

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Original post by Issy123
3/3 well done :smile:

Hcl can't be used as it reacts with the potassium manganate (VII).

Erm the Potassium Manganate is in the burette and the Iron is in the conical flask. The Potassium Manganate is slowly added to the conical flask and the Mn ions go from purple to pale pink when the end point is reached?

why is the first ionisation energy of Mg less positive than the second ionisation energy of Mg? [2 marks]


Ion is positively charged, greater attraction between nucleus and outer electron, more energy needed to overcome the attraction
Reply 781
Original post by otrivine
its fine :smile:

Describe how PH is controlled including an equation (6)


pH is controlled using a buffer solution. Buffer solutions are solutions that resist changes in pH when small amounts of acid or alkali are added.

A weak acid like ethanoic acid and the salt of the weak acid (sodium ethanoate) make up a buffer solution.


Ch3COOH-> Ch3COO- + H+ (the arrow should be reversible :colondollar: )

On addition of acid the equilibrium shifts to the left hand side as the extra H+ ions react with the ethanoate ion, removing most of the h+ ions added, preventing a fall in pH.

On addition of alkali the ethanoic acid dissociates and the OH- + H+ -> H20
The equilbirum shifts to the right hand side to restore most of the h+ ions, so a rise in pH is prevented.


Define the term lattice enthalpy with the use of an equation. :smile: [2 marks]
(edited 11 years ago)
Original post by The Illuminati
there is!! such as what, I thought F324 was mostly organic?


Stereoisomerism - optical/geometric isomers. There's polymerisation they've asked before.
Reply 783
Original post by The Illuminati
Ion is positively charged, greater attraction between nucleus and outer electron, more energy needed to overcome the attraction



yes 2/2 :smile:

define the term : standard electrode potential [3 marks]
Original post by Issy123
pH is controlled using a buffer solution. Buffer solutions are solutions that resist changes in pH when small amounts of acid or alkali are added.

A weak acid like ethanoic acid and the salt of the weak acid (sodium ethanoate) make up a buffer solution.


Ch3COOH-> Ch3COO- + H+ (the arrow should be reversible :colondollar: )

On addition of acid the equilibrium shifts to the left hand side as the extra H+ ions react with the ethanoate ion, removing most of the h+ ions added, preventing a fall in pH.

On addition of alkali the ethanoic acid dissociates and the OH- + H+ -> H20
The equilbirum shifts to the right hand side to restore most of the h+ ions, so a rise in pH is prevented.


Define the term lattice enthalpy with the use of an equation. :smile: [2 marks]


woow excellent 6/6 marks including QWC

lattice enthalpy is the entahlpy change when one mole of ionic compund is formed from its gaseous ions under standard conditons

For example
Mg(g) + cl2(g) to give mgcl2(s)
Original post by Killjoy-
That's exactly what you are saying - reasoning is the same.
Ratios as two chlorides are released per complex, so 1:2.


Justrealisedthat
Reply 786
Original post by otrivine
woow excellent 6/6 marks including QWC

lattice enthalpy is the entahlpy change when one mole of ionic compund is formed from its gaseous ions under standard conditons

For example
Mg(g) + cl2(g) to give mgcl2(s)


thank you! :smile: and 1/2 as the mg and cl must be ions, so Mg2+ and 2Cl- -> MgCl2
Original post by Issy123
thank you! :smile: and 1/2 as the mg and cl must be ions, so Mg2+ and 2Cl- -> MgCl2


snap yes true
Define:enthapy of neutralisation
Original post by otrivine
woow excellent 6/6 marks including QWC

lattice enthalpy is the entahlpy change when one mole of ionic compund is formed from its gaseous ions under standard conditons

For example
Mg(g) + cl2(g) to give mgcl2(s)


i think your wrong with your equation, isn't the lattice enthalpy equation of MgCl2:

Mg2+(g) + 2Clˉ(g) ==> MgCl2(s)
Original post by otrivine
snap yes true
Define:enthapy of neutralisation


the energy change that accompanies the neutralisation of an aqueous acid by an aqueous base to form one mol of H20(l) under standard conditions

define a standard conditions?
Reply 790
Original post by otrivine
snap yes true
Define:enthapy of neutralisation


the enthalpy change when an acid and alkali are neutralised to form 1 mole of water.

Why is the enthalpy change of neutralisation of ethanoic acid less exothermic than the enthalpy change of neutralisation of hydrochloric acid? [2marks]
(edited 11 years ago)
I love buffer solution questions, there always seems to be an explanation question that is usually always 5 marks, my teacher told us exactly what to write for 5 marks.

e.g. CH3COOH/CH3COONa buffer system

1. at equlibrium CH3COOH (equilibrium sign) CH3COO- + H+
2. adding acid causes CH3COO- + H+\rightarrowCH3COOH
3. euilibrium shifts to left
4.adding alkali causes OH- + H+\rightarrowH2O
5. equilibrium shifts to right


if there is a sixth mark you can say that there are large reservoirs of CH3COO- and CH3COOH
(edited 11 years ago)
Original post by kurdishboy94
the energy change that accompanies the neutralisation of an aqueous acid by an aqueous base to form one mol of H20(l) under standard conditions

define a standard conditions?


correct

298K,100KPA and 1 mol dm-3
Original post by Issy123
the enthalpy change when an acid and alkali are neutralised to form 1 mole of water.

Why is the enthalpy change of neutralisation of ethanoic acid less exothermic than the enthalpy change of neutralisation of hydrochloric acid? [2marks]


yes is correct but state conditions in case better

Becuase with ehtnaoic acid has weaker bonds less attraction and has OH groups which are weaker when bonding with another molecule and therefore less energy is needed to break the bonds
Original post by otrivine
yes is correct but state conditions in case better

Becuase with ehtnaoic acid has weaker bonds less attraction and has OH groups which are weaker when bonding with another molecule and therefore less energy is needed to break the bonds


I've never read this, where's it in the textbook/spec?
Original post by sumsum123
1) Adsorbed onto a material
2) Absorbed into a material
3) Liquify the hydrogen under high pressure

Explain why you cant use hydrochloric acid to acidify potassium manganate (VII) and describe how the titration experiment between potassium manganate (VII) and iron.


What's the answer to this? ^
Reply 796
Original post by otrivine
yes is correct but state conditions in case better

Becuase with ehtnaoic acid has weaker bonds less attraction and has OH groups which are weaker when bonding with another molecule and therefore less energy is needed to break the bonds


okay :smile: And thats true, although i think you have to mention that breaking the OH bond in ethanoic acid requires energy, so energy is used up, so its less exothermic? :smile:

Explain the advantages of Fuel Cell Vehicles over petrol and diesel powered vehicles. (3 marks)
Original post by LifeIsGood
I've never read this, where's it in the textbook/spec?


its the last page on enthalpy of neutralisation
Original post by Issy123
okay :smile: And thats true, although i think you have to mention that breaking the OH bond in ethanoic acid requires energy, so energy is used up, so its less exothermic? :smile:

Explain the advantages of Fuel Cell Vehicles over petrol and diesel powered vehicles. (3 marks)


greater efficieny
less co2 released
renewable(no burning of fossil fuels) does not contribute to global warming
Reply 799
Can anyone help me with question 7 on January 2011. It's a titration question, but seriously don't get what they've done on the markscheme.
How do they decide to quarter the number of moles of thiosulfate to get moles of oxygen? I can't see that relationship :/
Also confused about the units, mgdm-3, how do we get from moldm-3 to that?

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