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Edexcel As Chemistry Unit 3B

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Where can i get iodine thiosulphate titration procedure.. notes o just any stuff abt iodine thiosulphate titrations ??
Reply 81
Original post by TheMJCG
Hey! Does anyone know any website that can explain the different types of apparatuses needed for the different experiments, somehow I always get stuck on those questions.


From doing past papers and questions you could consider the following:

- Pippete normally measures 10cm^3 or 25cm^3 quantities
- Burette measures to an accuracy of 0.1 / 0.05cm^3
- Measuring cylinder measures to an accuracy of 1 / 0.5cm^3
how do u measure % error?
the question states: The error associated w/ reading the 25 cm^3 volume of potassium iodate (V) solution is +/- 0.06 cm^3

calculate the % error.

which one of the following do i do? :

1) ((0.06x2)/25) x100

OR
2) (0.06/25)x100

thanks in advance :biggrin:
Reply 83
Second one, and actually many people make this mistake.
I believe you multiply by 2 when your solution is a combination of 2 individually measured volumes.
Original post by Sellord
Second one, and actually many people make this mistake.
I believe you multiply by 2 when your solution is a combination of 2 individually measured volumes.


thanks a million :biggrin:
SO anything new? =P
Reply 87
http://www.thestudentroom.co.uk/showthread.php?t=97671&highlight=chemistry+unit+3b+edexcel+notes

This thread has notes that might be helpful!
Good luck to everyone :biggrin:
Reply 88
Original post by MarshmallowBob
:ninja: HAHAHAHAH yeah, I am! lol.


really? dude even im from riyadh ^__^
Reply 89
Does anyone have the 2012 January paper?
Reply 91
any 1 whose done the jan 2010 paper..plzzzz help me with the question no.4(f).......itz about percentage yield..but it deals with mols and volume
Original post by himi-patel
any 1 whose done the jan 2010 paper..plzzzz help me with the question no.4(f).......itz about percentage yield..but it deals with mols and volume


1 mol alcohol = 1 mol chloroalkane
0.2 mol alcohol = 0.2 mol chloroalkane

therefore, maximum mass of chloroalkane = (0.2 * 92.6) g
= 18.5 g

therefore, maximum volume of chloroalkane = (18.5 / 0.842) cm^3
= 22.0 cm^3

percentage yield = (18.7 / 22.0 * 100) %
= 85.0 %
Reply 93
Original post by solittletime
1 mol alcohol = 1 mol chloroalkane
0.2 mol alcohol = 0.2 mol chloroalkane

therefore, maximum mass of chloroalkane = (0.2 * 92.6) g
= 18.5 g

therefore, maximum volume of chloroalkane = (18.5 / 0.842) cm^3
= 22.0 cm^3

percentage yield = (18.7 / 22.0 * 100) %
= 85.0 %


THANK YOU SOO MUCH...i was looking at the marking scheme and my brain cells were damaging more.....finally settled in the brain.tnkxx
Reply 94
Can anyone explain the reason behind the answer for question 3(d)(v) of January 2010?
Original post by solittletime
1 mol alcohol = 1 mol chloroalkane
0.2 mol alcohol = 0.2 mol chloroalkane

therefore, maximum mass of chloroalkane = (0.2 * 92.6) g
= 18.5 g

therefore, maximum volume of chloroalkane = (18.5 / 0.842) cm^3
= 22.0 cm^3

percentage yield = (18.7 / 22.0 * 100) %
= 85.0 %


HAHAHA :biggrin: i like your name "SOLITTLETIME"!!
something we all say b4 exams!!

btw...
how to calculate percentage error?
and when do u multiply by 2? :s-smilie:
Original post by Sellord
Can anyone explain the reason behind the answer for question 3(d)(v) of January 2010?


Yeah coz u see the concentration doubles to 2moldm-3 from 1moldm-3 previously!
so temperature doubles :P

dont jus look at 50cm3 and 25cm3!> i did tht too first! :P
Reply 97
Original post by Lightuponlight
Yeah coz u see the concentration doubles to 2moldm-3 from 1moldm-3 previously!
so temperature doubles :P

dont jus look at 50cm3 and 25cm3!> i did tht too first! :P


So basically volume does not affect temperature change at all?
Can anyone explain when there should be a stopper in a reflux condenser?
In May 2010,question 4.b,the mark scheme says to not use a stopper,why?
Original post by The_New_Guy
Can anyone explain when there should be a stopper in a reflux condenser?
In May 2010,question 4.b,the mark scheme says to not use a stopper,why?


You should never, ever heat a closed system (by placing a stopper on top of a condenser as an example). Well okay, you can with specialised systems, but generally.

The increasing pressure caused by heating can lead to an explosion.
(edited 11 years ago)

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