Simple reversing a continued fraction expansion

I have to find a fraction such that [1;1,3,1,2]. I've done this so many times and I can get 25/14 but I should be getting (according to a continued fraction calculator online ), the result to be 25/9. I can point my working out if required but could somebody just check I am right if possible?

Your answer is correct.

25/9 would have to start [2;....,

Which online calculator are you using?

A continued fraction

[a_0;a_1,a_2,...]

is a number lying between

a_0

and

a_0+1

.

Your continued fraction is [1;1,3,1,2] and so must lie between 1 and 2, so no way can 25/9 be correct

OP

http://www.maths.surrey.ac.uk/hosted-sites/R.Knott/Fibonacci/cfCALC.html

this is what I've been checking against but maybe I just misinterpreted. I'm not sure.

Intriguing Alias

Original post by Preeka

http://www.maths.surrey.ac.uk/hosted-sites/R.Knott/Fibonacci/cfCALC.html

this is what I've been checking against but maybe I just misinterpreted. I'm not sure.

It said 25/14 when I just tried it.

Quick Reply

Latest

Trending

Trending

Articles for you

Your guide to handling revision and exam stress

Your guide to handling revision and exam stress

Students who got A*s at A-level explain study, learning and revision tips that everyone can follow

Students who got A*s at A-level explain study, learning and revision tips that everyone can follow

Best places online for maths revision

Best places online for maths revision

Students who got grade 9s at GCSEs share study tips that everyone can follow

Students who got grade 9s at GCSEs share study tips that everyone can follow