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2012 Higher Physics Discussion

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Original post by nECS
No idea, but when has logic ever stopped them? :L
I recall the chemistry one's where all laminated and shiny last year, maybe they can make some money recycling them or something?


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i meant what use would they be to you :tongue: They can just reuse them for next year, or give them to the teachers ( but teachers should have loads of data books anyway)
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Can anyone tell me what I am doing wrong here? The answer is A


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Original post by humza100
All my "Physics Abilities" are is being able to look up the answer and explain how to get it, it doesnt make me any better at physics, even now im procrastinating with the exam being tomorrow! :eek:


I don't even think it has sunk in yet that tomorrow is MY LAST EXAM WOOOO :biggrin:
Reply 1183
Original post by humza100
i meant what use would they be to you :tongue: They can just reuse them for next year, or give them to the teachers ( but teachers should have loads of data books anyway)


Idk then, maybe to satiate any burning desires you may have to know some electron arrangements? :L


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Original post by koolkate
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Can anyone tell me what I am doing wrong here? The answer is A


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9.67x10^-20 = 0.967x10^-19
Reply 1185
Original post by koolkate
ImageUploadedByStudent Room1369591433.331546.jpg
Can anyone tell me what I am doing wrong here? The answer is A


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9.67x10^-20 rounds to 1x10^-19
Just check the power of ten :smile:


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Original post by koolkate
ImageUploadedByStudent Room1369591433.331546.jpg
Can anyone tell me what I am doing wrong here? The answer is A


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Yes, look at the fact your answer is to ^-20 not ^-19. If you move the decimal place forward one place to give your answer to ^-19, it looks like 0.967x10^-19
i.e round up to answer A :smile:

EDIT: too slow :frown:
Original post by nECS
Idk then, maybe to satiate any burning desires you may have to know some electron arrangements? :L


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LOL, if your anything like me, you sometimes wake up in the middle of the night wondering want the GFM of Iodine is...

Original post by frances007
I don't even think it has sunk in yet that tomorrow is MY LAST EXAM WOOOO :biggrin:


Lucky you, still got 2 more after Physics :frown:
Guys- have any of you learned MOSFETs well? :/
Original post by humza100
LOL, if your anything like me, you sometimes wake up in the middle of the night wondering want the GFM of Iodine is...



Lucky you, still got 2 more after Physics :frown:


Which?!!
Reply 1190
Original post by humza100
LOL, if your anything like me, you sometimes wake up in the middle of the night wondering want the GFM of Iodine is...


I fear i may be worse than you, I actually knew what the GFM of Iodine was...gotta focus on physics, then chemistry :s-smilie:
Reply 1191
Original post by frances007
Guys- have any of you learned MOSFETs well? :/


Not at all. I've been thinking about learning it in detail but I've only learnt how to identify the source, gate and drain and also I think I needs +2v to be switched on


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Original post by TheFOMaster
9.67x10^-20 = 0.967x10^-19


Thanks can you also help me with these questions?
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Original post by ilyaasr
Not at all. I've been thinking about learning it in detail but I've only learnt how to identify the source, gate and drain and also I think I needs +2v to be switched on


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more than i know :colondollar:
Original post by frances007
Which?!!


Geography on 30th and Chemistry on 31st
Original post by frances007
Yes, look at the fact your answer is to ^-20 not ^-19. If you move the decimal place forward one place to give your answer to ^-19, it looks like 0.967x10^-19
i.e round up to answer A :smile:

EDIT: too slow :frown:


Thank you


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Original post by nECS
9.67x10^-20 rounds to 1x10^-19
Just check the power of ten :smile:


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Thanks :smile:


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Reply 1197
Original post by frances007
more than i know :colondollar:


haha! lets hope they don't come up!
Reply 1198
Original post by koolkate
Thanks can you also help me with these questions?
ImageUploadedByStudent Room1369593134.542214.jpgImageUploadedByStudent Room1369593211.938279.jpgImageUploadedByStudent Room1369593268.886456.jpg


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2) F = ma gives the unbalanced force, which in this case is 400N,
the weight is w = mg, which is 800N, thus, to overcome the weight and provide an unbalanced force of 400N, it must be 1200N (400+800)
so, C

12) Just check your value for the energy, don't think it's quite right

18) 1/Rt = 1/20 + 1/10 + 1/20
1/Rt = 4/20
Rt = 20/4
Rt = 5

so, B
Original post by koolkate
Thanks can you also help me with these questions?
ImageUploadedByStudent Room1369593134.542214.jpgImageUploadedByStudent Room1369593211.938279.jpgImageUploadedByStudent Room1369593268.886456.jpg


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Q2 youve got the force its travelling up at (400N) but first it needs to overcome its weight ( which youve also calculated at 800N) so the engine has to use a force of 800 + 400 = 1200N

Q12 - Dont know what you did to get E, but E is the difference between the two levels ( -5.4 - - 21.8 x10 -19 which is 16.4x10-19 then divide it by h, which gives 2.47 x1015 divide by speed of light and you get A

Q18 the two parralel circuits gives 20 ohms each so 1/Rt = 1/20 + 1/20+ 1/10 and gives you 5

EDIT - too late :frown:

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