AQA Mechanics 1B 24 May 2012 Unofficial Markscheme

They was two different parts of a question right? They mark each one individually so you will lose 1 mark on each for accuracy. But the method will certainly be right.

For all we know the exam may say "condone negative answer" im not sure. But my answer wasnt negative

Yes i opted for air resistance as the other assumption too (it was the only truly conclusive one imo), tbh a light peg also sounds good.

Jans boundary was really 68/75 for 100 UMS :O! I thought that paper was pretty easy, there was basically a whole 15 free marks for working out areas under straight line graphs! Certainly i can't see the boundaries for this paper being so low, though i'm at a loss to explain them for Jan's paper.

Talking to people at my school, i felt that people seemed to fall down on the end of question 7 (speed when travelling south east) and part of 8 (time above 5 meters). With regards to the later, a lot of people i talked to had actually solved the relevant quadratic but hadn't realised that they needed the difference between the two solutions. I suspect this will only cost them one of the marks though if they do show both solutions (as opposed to just quoting the larger solution only- then -2 marks imo).

Hopefully i'll get 95+ UMS but its more a matter of pride- i technically need between no UMS and 7 UMS in M1 depending on my c4 score to get an A/A* (again dependant on c4 performance) so it doesn't really matter. 1 exam down, 13 to go .

Yes i opted for air resistance as the other assumption too (it was the only truly conclusive one imo), tbh a light peg also sounds good.

Jans boundary was really 68/75 for 100 UMS :O! I thought that paper was pretty easy, there was basically a whole 15 free marks for working out areas under straight line graphs! Certainly i can't see the boundaries for this paper being so low, though i'm at a loss to explain them for Jan's paper.

Talking to people at my school, i felt that people seemed to fall down on the end of question 7 (speed when travelling south east) and part of 8 (time above 5 meters). With regards to the later, a lot of people i talked to had actually solved the relevant quadratic but hadn't realised that they needed the difference between the two solutions. I suspect this will only cost them one of the marks though if they do show both solutions (as opposed to just quoting the larger solution only- then -2 marks imo).

Hopefully i'll get 95+ UMS but its more a matter of pride- i technically need between no UMS and 7 UMS in M1 depending on my c4 score to get an A/A* (again dependant on c4 performance) so it doesn't really matter. 1 exam down, 13 to go .

For the projectiles question where you had to find out the time above 5 seconds, did you have to minus your smaller value of t from your larger one?

I never did this and stated my answer as the larger T.

I got the values right (if everybody elses is anything to go by) so id only lose one method mark so 4/5 anyway.

Suprised that was only 5 marks considering it was just as hard as the usual projectiles quadratic questions and a new situation. I cant remember them asking for that before "find the time above X"

But to be fair the two first parts of that question were worth 3 marks each and im sure theyre usually only worth 2, or one is usually 3 and the other 2 so a total of 5 instead of 6 like this time round.

I saved all my answers on my graphical calculator. I do not remember the questions, and will edit this thread according to the general feedback of the answers. Some of these may be wrong, again, these are simply my answers.

1a)5.39
b)338

2)0.5

3ai)? (Seemed to have not entered anything in for this question, though I did do it.
3aii)10
3aiii)2800N
3b)2600

4a)60
b)17.3
c)1.77

5a)5.88
bi)122.4
bii)117.6
biii)0.735
c)No air resistance, block is uniform in mass.

6a)Diagram, I think
b)NR = 78.4 - 0.5T
c)20.8

7a) s = (-i+3j)+0.5(0.1i-0.2j)t^2
b)30
c)1.41

8a) Angle was 61 degrees
b)19.6
c)43.4
d)3.69
e)10.8

Q7. Vectors/coordinate working of a particle in motion
a. s = (-i+3j)+0.5(0.1i-0.2j)t^2
b. Time = 30s
c. Speed = 1.41m/s

i dont understand for 7b how everyone got 30s? can someone explain this to me

The Jan paper was 73/75 for 100 UMS. How have you still got 13 exams to go?!?!

I left my answer and Root 2 instead of 1.41. Do you think I would lose any marks for that?

Jotted down my answers and here they are :

1a)5.39
b)338

2)0.5

3ai) -2
3aii)10
3aiii)2800
3b)2600

4a)60
b)17.3
c)1.77

5a)5.88
bi)122
bii)118
biii)0.735
c)No air resistance, block is a particle.

6a)Diagram
b)NR = 78.4 - 0.5T
c)23.5

7a) s = (-i+3j)+0.5(0.1i-0.2j)t^2
b)30
c)1.41

8a) -
b)19.6
c)43.4
d)3.45
e)10.9

Hope this helps

damn due to stupid errors i think ive dropped around 10 marks. what would 65 ums be? anyone

Jotted down my answers and here they are :

1a)5.39
b)338

2)0.5

3ai) -2
3aii)10
3aiii)2800
3b)2600

4a)60
b)17.3
c)1.77

5a)5.88
bi)122
bii)118
biii)0.735
c)No air resistance, block is a particle.

6a)Diagram
b)NR = 78.4 - 0.5T
c)23.5

7a) s = (-i+3j)+0.5(0.1i-0.2j)t^2
b)30
c)1.41

8a) -
b)19.6
c)43.4
d)3.45
e)10.9

Hope this helps

Why are you asking for 65 ums when you said you've lost 10 marks... if that's it you'll be at 70+ ums .
Btw if you want to find out an estimate do 0.65*75..

This was posted from The Student Room's Android App on my GT-N7000

Holy shot .... you hit the jack pot... you got all of them correct.... may I ask do you do physics - its understandable if you do physics from As cause this is so easy for people who are also taking physics....

This was posted from The Student Room's Android App on my GT-N7000

Whats the grade boundaries usually for mechanics?