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C1 - Differentiation :)

Can someone guide me in the right direction with the following question:

The curve with equation y=ax2+bx+cy=ax^2+bx+c passes through the point (1,2). The gradient of the curve is zero at the point (2,1). Find the values a,b and c.

umm what I have done so far, not sure if it is right..

2= a+b+c
dy/dx= 2ax+b
When 2 is subbed in the gradient = 0?
4a+b=0

Is that right?? :s-smilie: What do I do next?
Thanks
Original post by Super199
...


The gradient of the curve is zero at the point (2,1).

Unparseable latex formula:

\therefore \ \left \dfrac{dy}{dx} \right|_{(2, 1)} = 0



Unparseable latex formula:

\implies \left \left( 2ax+b \right) \right|_{(2, 1)} = 0



    2a(2)+b=0\implies 2a(2) + b = 0
Reply 2
Original post by Super199
Can someone guide me in the right direction with the following question:

The curve with equation y=ax2+bx+cy=ax^2+bx+c passes through the point (1,2). The gradient of the curve is zero at the point (2,1). Find the values a,b and c.

umm what I have done so far, not sure if it is right..

2= a+b+c
dy/dx= 2ax+b
When 2 is subbed in the gradient = 0?
4a+b=0

Is that right?? :s-smilie: What do I do next?
Thanks


You also know that (2,1) is a point on the curve, so you can set up a third equation :smile:
Reply 3
Original post by davros
You also know that (2,1) is a point on the curve, so you can set up a third equation :smile:

Got it thank you :smile:

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