Rearranging for y

How do I rearrange the graph log^2(x^3-12/7x+3)=10^y

Raise both sides to base 2, use laws of indices and then it shouldn't be too difficult.

Original post by Arithmeticae

Raise both sides to base 2, use laws of indices and then it shouldn't be too difficult.

Wait by raise to the base 2 do you mean log to the base of 2??

Wait by raise to the base 2 do you mean log to the base of 2??

No. I mean do

2^{\text{LHS}} = 2^{\text{RHS}}

Original post by Arithmeticae

No. I mean do

2^{\text{LHS}} = 2^{\text{RHS}}

Right it's telling me that there's an imaginary component to the equation but that can't be right surely!!

Right it's telling me that there's an imaginary component to the equation but that can't be right surely!!

What exactly is your equation? The lack of brackets and strange notation is confusing me :s-smilie:

When you say

\log ^2 (x)

, do you mean

\log ( \log (x))

\log (2x)

\log _2 (x)

Log^2(x) is how we were taught to wright (log(x))^2

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