I HAVE BEEN TRYING TO DO THIS QUESTION BUT DONT KNOW HOW ?
PLEASE HELP ME.
SKETCH A GRAPH OF y=x2+2x+3
Factorise it to: (x+3)(x-1), then x=1 and x=-3 [THIS IS WHERE IT CROSSES X AXIS] And it crosses y axis at y=3. Plot this graph with the common shape of a quadratic and you're done
Factorise it to: (x+3)(x-1), then x=1 and x=-3 [THIS IS WHERE IT CROSSES X AXIS] And it crosses y axis at y=3. Plot this graph with the common shape of a quadratic and you're done
thats what i thought but (x+3)(x-1) gives you x2+2x-3 but it has to be y=x2+2x+3
Factorise it to: (x+3)(x-1), then x=1 and x=-3 [THIS IS WHERE IT CROSSES X AXIS] And it crosses y axis at y=3. Plot this graph with the common shape of a quadratic and you're done
This isn't the question the OP posted
OP, you'll see that you can't factorise your equation so I would recommend completing the square. Can you see what do to now?
i did that but i dont know what to do after i complete the square
i got
x=1+- square root of -2
i dont know how to go from there
E.g. y=x^2 + 4x + 5 Complete the square y=(x + 2)^2 + 1 The minimum value of (x + 2)^2 is 0 therefore The minimum point on the curve is where x+2=0 I.e. x=-2 and y=1
Op find the minimum point as this a positive quadratic curve. This gives it a minimum of -1 , 2 . Because the curve has no real roots it doesn't cross either the x or y axis so just hangs.
Op find the minimum point as this a positive quadratic curve. This gives it a minimum of -1 , 2 . Because the curve has no real roots it doesn't cross either the x or y axis so just hangs.