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Chemistry AS coursework question
My task is to determine the concentration of limewater solution. Here is the information I've been given:
- you are provided with 250 cm*3 limewater which has been made so that it contains approx. 1g dm*-3 of calcium hydroxide
- also available is hydrochloric acid which has a concentration of exactly 2.00 mol dm*-3(the acid is too concentrated to be used so must be diluted).
What i want to know is what should be my reasons for choosing 0.02 mol/dm3concentration of acid as this is what most the other people in my class are doing?
- you are provided with 250 cm*3 limewater which has been made so that it contains approx. 1g dm*-3 of calcium hydroxide
- also available is hydrochloric acid which has a concentration of exactly 2.00 mol dm*-3(the acid is too concentrated to be used so must be diluted).
What i want to know is what should be my reasons for choosing 0.02 mol/dm3concentration of acid as this is what most the other people in my class are doing?
It is just easier to calculate!
You can dilute the concentrated acid by adding 1 to 99 parts water.
For example, if you take 1 cm^3 of that concentrated acid, you would have 2*(1/1000) moles = 0.002 moles
Adding 99 cm^3 to this, will give you 0.002 moles/(100/1000 dm^3) = 0.02 M.
At this concentration, it should be safe to use; just don't drink it.
You can dilute the concentrated acid by adding 1 to 99 parts water.
For example, if you take 1 cm^3 of that concentrated acid, you would have 2*(1/1000) moles = 0.002 moles
Adding 99 cm^3 to this, will give you 0.002 moles/(100/1000 dm^3) = 0.02 M.
At this concentration, it should be safe to use; just don't drink it.
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