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C3: trigonometry

Question 3 linked below. The only way I could think of answering the question was using the quadratic formula, I'm sure there must be a quicker way of solving this. Also is this a valid answer as not all of the solutions are correct? The other solution gives an angle of -75 degrees.

http://i.imgur.com/0HnPHXrh.jpg
http://i.imgur.com/1NcYfJOh.jpg
(edited 9 years ago)
Reply 1
Original post by Nuvertion
Question 3 linked below. The only way I could think of answering the question was using the quadratic formula, I'm sure there must be a quicker way of solving this. Also is this a valid answer as not all of the solutions are correct? The other solution gives an angle of -75 degrees.

http://i.imgur.com/0HnPHXrh.jpg
http://i.imgur.com/1NcYfJOh.jpg


method is essentially correct.

you reject the other solution
Solid method bro, exactly what I would do
Reply 3
Original post by Nuvertion
Question 3 linked below. The only way I could think of answering the question was using the quadratic formula, I'm sure there must be a quicker way of solving this. Also is this a valid answer as not all of the solutions are correct? The other solution gives an angle of -75 degrees.

http://i.imgur.com/0HnPHXrh.jpg
http://i.imgur.com/1NcYfJOh.jpg


It's simpler than that. tan15=tan(4530)=...\tan 15= \tan(45-30)=...
Original post by BabyMaths
It's simpler than that. tan15=tan(4530)=...\tan 15= \tan(45-30)=...

No..... I don't think that can work
Reply 5
Original post by BabyMaths
It's simpler than that. tan15=tan(4530)=...\tan 15= \tan(45-30)=...


I was wondering why they mentioned tan(45).
Reply 6
Original post by Jono-Wolf
No..... I don't think that can work


Why do you think that?

I assure you that it does work.
Reply 7
Original post by Jono-Wolf
No..... I don't think that can work


It can using the compound angle formula and it removes the need of using the quadratic formula.
(edited 9 years ago)
Original post by Nuvertion
It can using the compound angle formula.

Sorry, just typed it into my calculater and it is fine, I actually didn't know, that you could that :smile:
Reply 9
Original post by Jono-Wolf
Sorry, just typed it into my calculater and it is fine, I actually didn't know, that you could that :smile:


Now try it without using your calculator. :smile:
Original post by BabyMaths
Now try it without using your calculator. :smile:

Without a calculator I would just do that same method as Nuvertion
Original post by Jono-Wolf
Without a calculator I would just do that same method as Nuvertion


tan15=tan(4530)=tan45tan301+tan45tan30=...\displaystyle \tan 15 = \tan(45-30)=\dfrac{\tan 45 - \tan 30}{1+ \tan 45 \tan 30}=...
Original post by BabyMaths
tan15=tan(4530)=tan45tan301+tan45tan30=...\displaystyle \tan 15 = \tan(45-30)=\dfrac{\tan 45 - \tan 30}{1+ \tan 45 \tan 30}=...

Thanks, now I understand better

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