C2 log questions.

Ok so for the first question I just need someone to confirm what I am doing is right cause i'm not completely sure i'm doing it right. Where as the other one I am completely stuck.

Log₂(x+1) - Log₂ x = Log₂7


So I know what to do but i'm confused do I work out this equation and make it equal Log7/Log2

There is no need to introduce log into this question .... I really cannot imagine what you did here

Do you know the log(a) + log(b) = log(ab) rule and the one for subtraction

Sorry I think it was worded badly on my part rather than anything else.
Yes I understand the laws of logs so log(a) + Log(b) = log(a/b)

However what I am confused by is the log₂7 at the end of the equation.
So normally say Log (x+3) - Log x = 1

I would then Anti log this and get (x+3)/x = 10

Sorry if I worded it poorly mate.

I assume that you meant - not +


So you know that $\log_2 \dfrac{x+3}{x} = \log_2 7$

So raise both sides to the power of 2 (anti log)

I did sorry I edited it after I realised, Today has been a long day.

Ok sorry if I am being really dumb but would Log₂​7 raised to the power of 2 just equal 7? I find logs really difficult -.-

That is correct

If log(a) = log(b) then a=b