For the triangle one i got
a= (0.5b+1) / (0.25b-1)
I put that in with values that would have worked and it came out with exactly 3 times the area on all occasions so hoepfully it's right!
Anyone else get the same?

Reply 185

username2004639

7

Original post by Ewarwoowa

I got 300 by working out what the surface area of enlarged shape was then scaling that down to the scale factor

If you do area, the scale factor must be squared. So even if the method was right I think it's still wrong

Reply 186

username2004639

7

Linear equation was (-4, 37) and (0,5) I think??? Anyone else remember?

(edited 8 years ago)

Reply 187

nick0399

Distance time graph

Original post by jb303

Can anyone remember the 3rd question? The one on the second page

Reply 188

Lola1244

5

what are we reckoning the grade boundaries will be for both papers :smile:

Reply 189

dsjifodsapgnh5

1

If I did well in the 3H but meh in the 4H will I still get an A star

Reply 190

nullifiedvoid

the right-angled triangle was 3 times bigger, so why multiply the other triangle's area by 3?

Reply 191

OrangePeelOK

4

The grade boundary averages from May 2004 - January 2014 have been:

A* = 81
A = 63
B = 45
C = 27
D = 14

:u:

Reply 192

Ewarwoowa

4

Hate to break it to you lot but since most people found 3H hard the average for 4H will go up even more as people worked harder and it was a standard paper so I wouldn't be surprised with an 82-85 A* grade boundary

Reply 193

unknowntsr

18

Original post by nullifiedvoid

the right-angled triangle was 3 times bigger, so why multiply the other triangle's area by 3?

so that they are equal and u can start solving it

6 is 3 times greater than 2

6 = 3 x 2

Reply 194

unknowntsr

18

Original post by Ewarwoowa

Hate to break it to you lot but since most people found 3H hard the average for 4H will go up even more as people worked harder and it was a standard paper so I wouldn't be surprised with an 82-85 A* grade boundary

yes i thin around 80 for 3h

85 ish for 4h

Reply 195

OrangePeelOK

4

Original post by Ewarwoowa

Hate to break it to you lot but since most people found 3H hard the average for 4H will go up even more as people worked harder and it was a standard paper so I wouldn't be surprised with an 82-85 A* grade boundary

Yeah, but they're not individual marks I thought? You get an average, right?

Reply 196

neelc21

8

Original post by Ewarwoowa

I got 300 by working out what the surface area of enlarged shape was then scaling that down to the scale factor

me too man but i think 120 is the right answer

yeah

Original post by QuantumPotato

i just did simultaneus equation 3(1/2absin150) = 1/2(a+1)(b+2) or something like that, at least 3 in my school including I have got (2b+4)/(b-4)

2b+4/b-4 is definitely right. Most notably because they said b>4 (therefore b-4 makes sense)

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Reply 199

gmahapatra

10

Original post by immyB01

If you do area, the scale factor must be squared. So even if the method was right I think it's still wrong

300 is wrong. But note that if you do area, you wouldn't square the scale factor (I think), because k^2^2 goes to k^4. You'd have to square root its cube, because k^2^1.5=k^3. I think.

Posted from TSR Mobile

Edexcel IGCSE Mathematics 4MA0 4H - 4th June 2015

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