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C4 double angle proof exam question help!

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Reply 1
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I dont understand the second step written in pencil how in the mark scheme it just multiplies 2sinxcosx by cosx on numerator and denominator. How is it not 2sinxcos^2x - sinx?
Original post by AndyOC
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I dont understand the second step written in pencil how in the mark scheme it just multiplies 2sinxcosx by cosx on numerator and denominator. How is it not 2sinxcos^2x - sinx?


Only the first term was multiplied by cos(x)cos(x)

2sin(x)cos(x)1cos(x)cos(x)\frac{2sin(x)cos(x)}{1}*\frac{cos(x)}{cos(x)}
(edited 8 years ago)
Reply 3
Original post by 123Master321
Only the first fraction was multiplied by cos(x)cos(x)

2sin(x)cos(x)1cos(x)cos(x)\frac{2sin(x)cos(x)}{1}*\frac{cos(x)}{cos(x)}


I didn't realise you could just do that, is it the same with all trig proof questions then?
Original post by AndyOC
I didn't realise you could just do that, is it the same with all trig proof questions then?


The reason you can do that is because you are effectively only multiplying by 1 as cos(x)cos(x)=1\frac{cos(x)}{cos(x)}=1
Im not sure what you mean " is it the same with all trig proof questions then"
Reply 5
Original post by 123Master321
The reason you can do that is because you are effectively only multiplying by 1 as cos(x)cos(x)=1\frac{cos(x)}{cos(x)}=1
Im not sure what you mean " is it the same with all trig proof questions then"


Ah yeah I see now don't worry, I was just a bit confused because i didn't really think about it like that. Thanks for the help!
Original post by AndyOC
Ah yeah I see now don't worry, I was just a bit confused because i didn't really think about it like that. Thanks for the help!



No problem!! Glad I could help

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