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AQA A Level Maths Core 1 - 18th May 2016 [Exam Discussion]

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Reply 380
that was ridiculously hard for a c1 paper, is there an unofficial mark scheme out yet?
Original post by ameekc
that was ridiculously hard for a c1 paper, is there an unofficial mark scheme out yet?


Yes. http://www.thestudentroom.co.uk/showthread.php?t=4095491 Please post any questions here.
Original post by timtjtim
Don't see why not - you used a valid method. I did the same - I thought that as A is across by 7 and up by 4 from C, B must be across by 7 and down by 4.


Haha I did the exact same thing - even drew a diagram. But C being the midpoint does seem to be the correct method though sadly, but it'd be great if we still got 2/2 marks for it anyway.
Reply 383
What was the full question were we had to find the second derivative, then prove there is is minimum point?
Original post by laur a
can anyone remember the actual quadratic we had to factorise for that question as defo got -3/2 but cant remember the other number :frown:


Exactly what I want to know.

Original post by timtjtim
(2x-3)(x+6)


Are you sure the signs aren't the other way around?

Original post by Crespo0008
I got the wrong answer for the area for the shaded region as I intergrated the y=-32x-40 instead of doing the triangle thing, will I lose all the marks?


Ay, i did the same thing, didn't realise the whole triangle thing and got the wrong answer too. Let's hope we get even just one mark for trying? I doubt the examiners would be so kind.


Original post by SM-
What was the full question were we had to find the second derivative, then prove there is is minimum point?


Yes I'd like to know this too.
Original post by timtjtim
Yes, -5/4 was the x-coordinate of Q


okay thanks at least i did one thing right
what was the answer for the geometric transformation ?
Original post by BlackthornRose
Exactly what I want to know.



Are you sure the signs aren't the other way around?


Don't think they are!
Original post by aliyaahh
what was the answer for the geometric transformation ?



For the mark scheme, look at https://docs.google.com/document/d/1iNmYSXMwLW0RID8A4Yk__VQINLjQZuPljHsUdbsfoj4/edit
Original post by timtjtim
Don't think they are!


Wait, is this the one with the answers x<-3/2 and x>6?

If so, what was your working out?

Sorry about the questions and thank you for your help :smile:
Who is going to be ready for C2?
Oh and the people who done edexcel got it hard for C1
(edited 7 years ago)
Reply 392
Did we had to verify a point as the maximum where we found the second derivative where x was -1.5?
I found that the area of the triangle was 9 and I got the area under the curve as 243/12(or 20.25). So 20.25-9 would give you 11.25. Hope that helped, I can't remember the exact working out !
Original post by SM-
What was the full question were we had to find the second derivative, then prove there is is minimum point?


oh i think it was dy/dx= 54-3x^3-6x well I'm pretty sure it was that
Original post by Darshhchiba
same I got root 34 because the only information that was given was the centre so how could you get root 65?!?!


There was also a point A too... But I skimmed over this and I got root 34 too (by doing the same method as you)... But the general consensus is that it's root 65...
Original post by Darshhchiba
same I got root 34 because the only information that was given was the centre so how could you get root 65?!?!


You were given point A
Original post by BlackthornRose
Wait, is this the one with the answers x<-3/2 and x>6?

If so, what was your working out?

Sorry about the questions and thank you for your help :smile:


I'm sorry, all I have are the answers here right now.
[QUOTE="WhiteTigerKURD;64908715"]I found it alright but struggled on the question where it asked for CT and gave you AT[/QUOTE

T to the center and AT form a right angle triangle, as it is a normal to a tangent. So then you could use what you know, AT is 6 or whatever it said and the radius you know is root65 so then just had to use Pythagoras
Original post by WhiteTigerKURD


T to the center and AT form a right angle triangle, as it is a normal to a tangent. So then you could use what you know, AT is 6 or whatever it said and the radius you know is root65 so then just had to use Pythagoras


AT was 4, so 65 + 4^2 = 81. Root 81 = 9.

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