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AS1 Pure maths differentiation question HELP

3√x/2+8/x+1

does anyone know how to solve this question by using dy/dx ??
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You need to express the roots as fractional powers and then you can use the normal rules of differentiation
Original post by computerwizz
3√x/2+8/x+1

does anyone know how to solve this question by using dy/dx ??


Firstly you haven't defined y.
Secondly, what do you mean "by using dy/dx"? Do you mean "how do I differentiate this expression"?
Original post by RDKGames
Firstly you haven't defined y.
Secondly, what do you mean "by using dy/dx"? Do you mean "how do I differentiate this expression"?


yes
Original post by nerak99
You need to express the roots as fractional powers and then you can use the normal rules of differentiation


can u please explain how to do that please? I don't understand?!
Original post by computerwizz
can u please explain how to do that please? I don't understand?!


x=x1/2\sqrt{x}=x^{1/2} and 1x=x1\frac{1}{x}=x^{-1} so just use these definitions.
Original post by RDKGames
x=x1/2\sqrt{x}=x^{1/2} and 1x=x1\frac{1}{x}=x^{-1} so just use these definitions.


okay thanks
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I will assume that is y = 3/2 * x + 8/x +1

Can re-write this as y = 3/2 * x1/2 + 8x-1 + 1

dy/dx = ¾ * x-1/2 8x-2 + 0

or dy/dx = 3/4x 8/x2

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