I'm very confused because we are finding the mean, so surely we are thinking about biased estimates for the mean I don't understand why its an estimate for a?
Please help @Gregorius I would be so grateful!

(edited 5 years ago)

Reply 4

Gregorius

14

Original post by examstudy

what I dont understand is because we are finding the mean, so surely we are thinking about biased estimates for the mean I'm really confused where its suddenly a, when 3/2 a is the mean?
Please help @Gregorius I would be so grateful!

You already have an open thread on this question. Please do not open multiple threads in the future.

Just this once, however... you are asked to find an unbiased estimator of alpha - where alpha is not the mean of the distribution.

\bar{X}

is an unbiased estimator of the mean of the distribution. The question asks you to fiddle with

\bar{X}

to give you an unbiased estimator of alpha.

Reply 5

examstudy

OP

10

Sorry, I didn't know how to get attention to it, I won't in future.

Thank you for responding but I'm not sure I follow 100%.
We know the unbiased estimator of the mean is X bar and is 3/2 a, yes?
How does this show that X bar is a biased estimator of a? We only know about estimations of the mean?This is where I am lost. :s-smilie:

(edited 5 years ago)

Original post by examstudy

Sorry, I didn't know how to get attention to it, I won't in future.

Thank you for responding but I'm not sure I follow 100%.
We know the unbiased estimator of the mean is X bar and is 3/2 a, yes?
How does this show that X bar is a biased estimator of a? We only know about estimations of the mean?This is where I am lost. :s-smilie:

@Gregorius

If X bar is an unbiased estimator of the mean, this means that the expected value of X bar is the mean, that is, (3/2)a.

If X bar were an unbiased estimator of alpha, we would have to have the expected value of X bar equal to alpha.

Reply 7

examstudy

OP

10

Original post by Gregorius

If X bar is an unbiased estimator of the mean, this means that the expected value of X bar is the mean, that is, (3/2)a.

If X bar were an unbiased estimator of alpha, we would have to have the expected value of X bar equal to alpha.

Thank you

Statistics pls help asap

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