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3rd tickbox for the indicator used for that graph
Original post by CeliaaaWuuu
don't you need to multipying the 107 by 2? for the atomisation enthalpy change of iodine.


That’s what I did!
Original post by Abdidoodle
what was the shape of POCl3 btw??
Ik that ClF3- was square planar with 90degrees


Tetrahedral
Krypton was most electronegative
Did anyone get for the pressure as 1.73 ×10 to the power 5? Also the next question was the square root of 3.94 x 104.
Reply 25
For ka I got 9.9*10^-18 but it seems too large
Original post by Khushi.S
Feel free to add yours answers and then I can order them
I got (in no order)
192000 for the Kp question
169 for the relative molecular mass
750 for the ideal gas law equation
4.3 for the buffer solution
46.4% for the titration
333Kjmol-1 for the entropy
107 for atomisation


1.1) Equations- Cd(s)+ 1/2I2(s) and then Cd+(g)+e-+I
1.2) 107 (bit of a debate about this one)
1.3) Some covalent character?
1.4) 333kJmol-1 and since G>0, its not feasible

Acids and Bases Question:
4.57 * 10^-14
4.30
The third box on the table
For Ka- had to use half neutralisation point but can't remember what I got


Question with the Fe complexes
Fe(OH)3(H2O)3
Brown Colour
2[Fe(H2O)G]3+ + 3CO32- => 2[Fe(H2O)3(OH)3] + 3CO2 +3H20
FeCl3? and then equation with 3 Cl-
Fe(H2O)4(OH)2 and green precipitate

Question about Period 4
Most electronegative- Bromine
Potassium had the smallest atomic radius due to least number of protons- least attraction between outer shell of electrons and the nucleus
Amphoteric

Titration
Percentage by mass of carbon is 46.4%
To increase the accuracy- use a larger mass of solid or less concentrated thiosulphate
Iodine acts as the oxidising agent?
Its white because it has a full d orbital and so, cannot absorb any light and emits all of it so looks white

These are all the maths ones (almost) so feel free to add


Wasnt the ideal gas equation around 7500. 5/(2×126.9) × 8.31 × 473 / 100000 ×10^6. Just ****ing realised i had a calculator error. So pissed.
(edited 4 years ago)
defo 107 i checked by recalculating the cycle
Reply 28
Did anyone get the iron complex + HCL
Oh well done, was just losing hope
Original post by iamjosephvella
defo 107 i checked by recalculating the cycle


:redface:
(FeCl4)- looked right ?
Original post by ezoomer
Did anyone get the iron complex + HCL
[Fe(H20)6]3+ + 4Cl- --> [FeCl4]- + 6H20
Original post by ezoomer
Did anyone get the iron complex + HCL
Reply 32
What was the answer to the relative mass of Q - i put 170
Original post by Khushi.S
I thought atomisation was already set for 1/2?


It was already a half yes. But the question wanted the full figure of atomisation. So you had to multiply by 2 in the end
Original post by TheLegend25
(FeCl4)- looked right ?

I put FeCl3 because the iron was in the +3 form?
well i flopped everything else expect ph which was 4.30
Original post by Anisha12
Oh well done, was just losing hope


:redface:

Spoiler



Original post by Aadz7
I also did x2
Original post by hafsah307
What was the answer to the relative mass of Q - i put 170

169
how many other people forgot the 2 in front of the iron
What did everyone get for The buffer question??

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